Customcontrol has a property, but it lost on saved. Like control.cousor(from cursors--static property).

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I'm so sorry for my enlish.
I writed a control which has a property named Associa(class). And this property reference from a static class. when i designed and saved Form, this property have lost。

Code：

public sealed class Associa
{
    private string _FunCode = "NULL";

    /// <summary>
    /// 构造
    /// </summary>
    private Associa()
    {
    }

    public string FunCode
    {
        get { return this._FunCode; }
        private set
        {
            if (string.IsNullOrEmpty(value))
            {
                value = "NULL";
            }

            if (this._FunCode != value)
            {
                this._FunCode = value;
            }
        }
    }

    public static Associa Generate(string pcFunCode)
    {
        Associa loAssocia = new Associa();
        loAssocia.FunCode = pcFunCode;
        return loAssocia;
    }

public static class AssociaFactory
{
    public static Associa NULL = Associa.Generate("NULL");

    public static Associa pubvocabulary = Associa.Generate("pubvocabulary");
}

used by:
this code in designer file

this.control.Associa = AssociaFactory.NULL

it lost on saving

What I have tried:

i watch the code "Control.Cursor",but has no idea.....

Posted 18-Sep-16 23:58pm

AdaEniac

Updated 22-Sep-16 1:12am

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Comments

BillWoodruff 19-Sep-16 9:16am

Not clear what you are doing here. What is your goal ? When you mention "saving" it's logical to assume some form of serialization ... but, your code shows no attempt to serialize or de-serialize.

Ralf Meier 19-Sep-16 13:48pm

I think the OP wants that the property-value is "saved" by the designer. But for me this "CustomControl" makes no sense in this way. Perhaps more information is required ...

AdaEniac 19-Sep-16 21:46pm

Yes. I want that the property-value is "saved" by the designer.

Ralf Meier 20-Sep-16 15:26pm

OK ... show (improve your question with) the code where you use Associa as a Property ...

AdaEniac 21-Sep-16 3:46am

Well，i want simulate System.Windows.Forms.Cursor.
As you know, "Control.Cursor" is from Cursors. So, when you saved a Form, you can see the property which named "Cursor" in the XXX.Designer.cs file.
like this "this.Cursor = System.Windows.Forms.Cursors.Default".

So, how can i save my property like "Cursor"

Ralf Meier 21-Sep-16 3:55am

Sorry - I can't follow you ... :(
What I understood is : you have build a class and want to use this class as a Property with your own custom Control. For this I want to see the Property-code where you tried to realize this.
What I not understood is : for what do you need the Cursor-Property in this context ?

Perhaps I understood your requirement complete wrong. If Yes : please explain once more with more information ...

AdaEniac 21-Sep-16 4:15am

EXP

public class TestControl : System.Windows.Forms.Control
{
private Associa _Associa = Associas.NULL;

public TestControl()
{
}

public Associa Associa
{
get { return _Associa; }
set { _Associa = value; }
}
}

Ralf Meier 21-Sep-16 9:15am

see my Solution (2)

AdaEniac 21-Sep-16 22:11pm

sorry。。。

i know this, but it had no effect

Ralf Meier 22-Sep-16 5:28am

I modified my Solution - take a look ...
I think. that your generell problem was that the Setter of FunCode was Private ... (why ?)

AdaEniac 22-Sep-16 7:14am

thank you very much

Ralf Meier 22-Sep-16 14:10pm

You are welcome ...
Thanks for your voting ... :)

AdaEniac 22-Sep-16 22:08pm

I think. that your generell problem was that the Setter of FunCode was Private ... (why ?)

Well, some times ago, we used Enum in base Dll. but Enum is unscalable as you know. so, i want simulate System.Windows.Forms.Cursor.

Control.Cursor which is referenced from Cursors, and Cursors is a static class
In this way, it is easy to extend the derived class

Ralf Meier 23-Sep-16 14:11pm

Sorry ... I don't understand you ...
Please explain once more ...
Do you need additional help to something ?

AdaEniac 26-Sep-16 4:56am

no, thank you

AdaEniac 29-Dec-18 2:26am

yes

Ralf Meier 30-Dec-18 15:50pm

Yes ...???
What do you mean ...???

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Ralf Meier · Accepted Answer · 2016-09-21T03:15:00

with your class-Property try it like this :

[System.ComponentModel.DesignerSerializationVisibility(System.ComponentModel.DesignerSerializationVisibility.Content)]
public Associa Associa
{
	get { return _Associa; }
}
private Associa _Associa = new Associa();

your class itself I modified like this :

[System.ComponentModel.TypeConverter(typeof(System.ComponentModel.ExpandableObjectConverter))]
public class Associa
{

	public string FunCode {
		get { return this._FunCode; }
		set {
			if (string.IsNullOrEmpty(value)) {
				value = "NULL";
			}

			this._FunCode = value;
		}
	}

	private string _FunCode = "NULL";
	public static Associa Generate(string pcFunCode)
	{
		Associa loAssocia = new Associa();
		loAssocia.FunCode = pcFunCode;
		return loAssocia;
	}

	public Associa()
	{
		_FunCode = "NULL";
	}

	public Associa(string pcFunCode)
	{
		_FunCode = pcFunCode;
	}


	public override string toString()
	{
		return _FunCode;
	}

}

now it should work like you want ...