How to print the matrix?

Question

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I wants to print matrix such that

Consider that original matrix look like following

1 2 3 
4 5 6
7 8 9

Now I want to print like following

step1: print 1

step2: print 2

step3: print 3

step4: print 6

step5: print 9

step6: print 8

step7: print 7

step8: print 4

step9: print 5

1 2 3
    6  first step
    9

1 2 3
    6 second step
  8 9


1 2 3
    6 3rd step
7 8 9

1 2 3
4   6 4th step
7 8 9

1 2 3
4 5 6  5th step 
7 8 9

What I have tried:

i have tried to display the code above manner?

Posted 23-Sep-16 2:31am

bala g ch

Updated 23-Sep-16 4:07am

Patrice T

v5

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[no name] 23-Sep-16 8:33am

I hate to be the one to tell you this, but the isn't a single loop, inner or outer, in the code that you have shown us that demonstrates whatever your problem is.

[no name] 23-Sep-16 8:35am

suppose i have matrix A(3*3).
i want to print the that matrix in following manner:-

for an example:

->A11,A12,A13,A23,A33,A32,A31,A21,A22 how can i print the matrix in following manner.

Leo Chapiro 23-Sep-16 8:44am

As @NotPolitcallyCorrect already said, show us your code please, we can't read your mind, dude!

[no name] 23-Sep-16 8:46am

As per my company policy it is not possible show my code to you.

Leo Chapiro 23-Sep-16 8:50am

But it seems to be possible (as per your company policy) to ask for help in this forum. And there are rools here: you need to show what you already achieved before ask for code ...

[no name] 23-Sep-16 8:52am

Then you need to go to a site that can read your mind. We aren't going to do your work for you. Nice try.

Nelek 23-Sep-16 8:54am

mmm... I just edited this to answer below

[no name] 23-Sep-16 8:57am

Yeah, "Against company policy" tells me that his teacher is checking the online forums for cheaters. Especially looking back over his history of asking really basic no effort made questions.

[no name] 23-Sep-16 9:12am

This is not basic work.actual this task is very complicated.If your a genius provide it the answer otherwise do that thing?

Richard MacCutchan 23-Sep-16 10:03am

No it is not very complicated. It is a fairly simple test designed to demonstrate what you have learned in your course. It is not designed to test whether you can get other people to do your work.

Nelek 23-Sep-16 10:03am

Ok... I have to admit, when I wrote the first comment, I had not taken so much attention to your serie. I can admit, that this is not a basic question. But neither a very complicated one.

On the other hand, you are lucky that I didn't read this comment before I clicked the "post answer" button, and that after the effort of thinking about a way to solve it and writing the answer I am not willing to delete it.

Patrice T 23-Sep-16 9:07am

Too bad, as per site policy, we can't help you with code :-)

[no name] 23-Sep-16 9:12am

Ok leave it i am trying?

jeron1 23-Sep-16 9:59am

That is a good one! Maybe try the algorithms forum if no code is to be involved.

Nelek 23-Sep-16 10:19am

Answers are already there :)

Philippe Mori 23-Sep-16 13:01pm

Then don't show existing code from your company but code you wrote yourself... You can always simplify code so that we got the essential. Just don't forget to remove your database password!

By the way, it should not be hard to do this.

And how can we answer you if you cannot share your company code. If you use the code we provide, then your company code would be partly on the web...

You need to have some common sense and discuss with your company if you want to shpw some code. Maybe, they would think you are not competent enough for the job and replace you by someone else...

Patrice T 23-Sep-16 8:59am

Do you want to print the matrix elements in spiral order ?

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Nelek · Accepted Answer · 2016-09-23T04:02:00

First of all... sorry but one note aside:
That your company rules don't allow to show code... it is perfectly understable and I find it very good that you follow the rules.
But...
You are asking for help, repeating 3 times the same sentence doesn't clarify anything.
If you don't want to show the code of the company, then don't do it, but at least you still can use pseudo-code to explain the steps you are doing and where are you getting problems
Learn how to use the debugger. This is something you should be able to solve on your own actually pretty quick

Please don't take it personally, it is not an attack against you, just a philosophical question: Are you sure you are prepared to do this job?
And I am not speaking about the technical content, everyone is a newbie at the beggining. I am thinking on other habilities... i.e. curiosity, tenacity, logical thinking and others related.

I would recommend you to try it first on your own and learn from your mistakes, this is the best school you can get. Don't give up easily and come here to ask. Of course it is confortable and you will probably always find someone that answers you. The most important point is... you won't learn so much and you will miss a very big reward for your soul, that is the satisfaction of being able to solve things on your own.

----------------------
Now to the technical side. I am not going to give you a ready solution, and probably there are better ways to solve this, but... it is still a way that you can infere / guess just taking paper and pencil and doing 2 or 3 examples to search for a pattern:

Assuming a Matrix A(MxN) no matter M and N values

1) Think on going through your matrix as squares / rectangles, each of them is one full iteration. You will need so many iterations as the ((smallest index / 2) + (smalles index % 2))
i.e.
A(2x6) = 2/2 + 2%2 = 1 rectangle or iteration
A(6x3) = 3/2 + 3%2 = 2 rectangles or iterations
A(7x7) = 7/2 + 7%2 = 4 rectangles or iterations

2) How do you do each square?
Line 1: From A(1+squareNr, 1+squareNr) to A(1+squareNr, N-squareNr)
Line 2: From A(1+squareNr, N-squareNr) to A(M-squareNr, N-squareNr)
Line 3: From A(M-squareNr, N-squareNr) to A(M-squareNr, 1+squareNr)
Line 4: From A(M-squareNr, 1+squareNr) to A(1+(squareNr+1), 1+squareNr)

3) You end when you reach the last element = M*N
A(2x6) = 12
A(6x3) = 18
A(7x7) = 49

4) Now you only have to figure out how to use the loops and the conditions to manage this. Point 2) is considering 0-based iterations, adapt it if you prefer start counting in 1

edits to correct spelling and make sentence more coherent

OriginalGriff · Accepted Answer · 2016-09-23T04:07:00

This smells of homework, so no code!
It's not difficult, it's just cumbersome.
Declare eight variables: X, Y, dX, dY, minX, maxX, minY, maxY.
Set them to 0, 0, 1, 0, 0, width, 0, height respectively.
Now set up a loop to look at each cell: width * height.
Inside the loop, print the X,Y cell.
Now add dX to X and dY to Y.
Check X:
If it's equal to maxX then reduce it by one, increment y by one, increment minX, and set dX to 0, dY to 1.
If it's equal to minX then increment it by one, reduce y by one, decrement maxY, and set dX to 0, dY to -1.
Check Y:
If it's equal to maxY then reduce it by one, decrement x by one, decrement maxX, and set dX to -1, dY to 0.
If it's equal to minY then increment it by one, increment x by one, increment minX, and set dX to 1, dY to 0.

That should do it.

How to print the matrix?

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