How to Find repeated Charaters in a String?

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Hi,
How to Find Repeated Characters in a string using C Program.

Can Any one help me?

regards
Sarath

[edit]Tags only - OriginalGriff[/edit]

Posted 30-Sep-10 22:53pm

sarathbabununna

Updated 30-Sep-10 23:30pm

OriginalGriff

v2

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Sandeep Mewara 1-Oct-10 11:44am

No effort

3 solutions

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OriginalGriff · Answer 1 · 2010-09-30T23:31:00

Solution 1

Loop through each character in the string, checking it against the last one.
Which bit of this are you having problems with?

Posted 30-Sep-10 23:31pm

OriginalGriff

Aescleal · Answer 2 · 2010-10-01T01:54:00

Solution 2

Create an array of bits, one per possible character. Read each character in turn and set the corresponding bit in the arry. Bail out if you try and set a bit that's already set.

Cheers,

Ash

PS: Unless you mean two characters the same next to each other in the string, in which case Griff's answer is the way to go.

Posted 1-Oct-10 1:54am

Aescleal

Comments

OriginalGriff 1-Oct-10 9:35am

5! I hadn't thought of that interpretation - good thought. I would probably just sort the characters then treat as for my interpretation though.

bkravibabu · Answer 3 · 2010-11-01T20:52:00

#include<stdio.h>
struct verify
{
char s;
int flag;

}pt[100];
struct count
{
char q;
int count;
}st[100];

main()
{
char p[100];// = "LIFETREE";
int i, j,k;
printf ("enter the string \n");
scanf("%s", p);
for(i;p[i] != '\0'; i ++)
{
pt[i].s=p[i];
pt[i].flag=0;
}
p[++i] ='\0';
for(i=0;p[i] != '\0' ;i++)
{

st[i].q=p[i];
if(pt[i].flag == 0)
{

st[i].count=1;
pt[i].flag = 1;
for(j = i+ 1;p[j] != '\0'; j++)
{
if(p[i] == p[j])
{
st[i].count += 1;
pt[j].flag =1;
}
}
}
}
for(k = 0;k < i;k ++)
{
if(st[k].count > 0)
printf ("%c %d\n", st[k].q,st[k].count);
}

}