Get richtextbox caret position index number

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Hello All,
I am using a richtextbox and i need to get the caret position as number in order to use it , any idea to get the index number ??
thanks for your help

What I have tried:

i don;t find anythimg and i don't find any function in richtextbox function that return to my the index number

Posted 28-Jan-17 0:02am

Member 12945224

Updated 28-Jan-17 1:31am

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2 solutions

Solution 2

You can use RichTextBox.CaretPosition[^] property to access the current index of caret inside the content.

Following code was captured from MSDN,

// Create a new FlowDocument, and add 3 paragraphs.
FlowDocument flowDoc = new FlowDocument();
flowDoc.Blocks.Add(new Paragraph(new Run("Paragraph 1"))); 
flowDoc.Blocks.Add(new Paragraph(new Run("Paragraph 2"))); 
flowDoc.Blocks.Add(new Paragraph(new Run("Paragraph 3")));
// Set the FlowDocument to be the content for a new RichTextBox.
RichTextBox rtb = new RichTextBox(flowDoc);

// Get the current caret position.
TextPointer caretPos = rtb.CaretPosition;

// Set the TextPointer to the end of the current document.
caretPos = caretPos.DocumentEnd;

// Specify the new caret position at the end of the current document.
rtb.CaretPosition = caretPos;

You can see that these are a few of the methods how you can manipulate the caret position inside the document, you can get the position, as well as set the position.

Posted 28-Jan-17 1:31am

Afzaal Ahmad Zeeshan

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OriginalGriff · Accepted Answer · 2017-01-28T00:08:00

Solution 1

Google is your friend: Be nice and visit him often. He can answer questions a lot more quickly than posting them here...

A very quick search using your subject as the search term gave 30,000 hits: Get richtextbox caret position index number WPF - Google Search[^]
Leading almost immediately to MSDN: RichTextBox, getting caret index.[^]

In future, please try to do at least basic research yourself, and not waste your time or ours.

Posted 28-Jan-17 0:08am

OriginalGriff

Comments

Member 12945224 28-Jan-17 6:31am

thank you for your help and i will not waste your time again. and i will do more researches for my problems. thx again

OriginalGriff 28-Jan-17 6:51am

You're welcome!