Root element is missing when deserialize XML , ASP

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i get xml file from service , but i have problem when i want

Deserialize

to object ,, always show me

root element is missing

xml

XML

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfResultInfo xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://tempuri.org/">
<ResultInfo>
<PartNumber>KRPA-4007</PartNumber>
<Manufacturer>test</Manufacturer>

</ResultInfo>
</ArrayOfResultInfo>

code

C#

string xml = null;
     WebRequest req = WebRequest.Create(link);
     req.Credentials = CredentialCache.DefaultCredentials;
     WebResponse res = req.GetResponse();
     Stream dataStream = res.GetResponseStream();
     StreamReader reader = new StreamReader(dataStream);
     xml = reader.ReadToEnd();
     XmlSerializer serializer = new XmlSerializer(typeof(ArrayOfResultInfo));
     var result = (ArrayOfResultInfo)serializer.Deserialize(reader);

What I have tried:

string xml = null;
WebRequest req = WebRequest.Create(link);
req.Credentials = CredentialCache.DefaultCredentials;
WebResponse res = req.GetResponse();
Stream dataStream = res.GetResponseStream();
StreamReader reader = new StreamReader(dataStream);
xml = reader.ReadToEnd();
XmlSerializer serializer = new XmlSerializer(typeof(ArrayOfResultInfo));
var result = (ArrayOfResultInfo)serializer.Deserialize(reader);

Posted 19-Feb-17 20:55pm

ÂĦmâd Ŝâlâĥ

Updated 20-Feb-17 1:54am

v2

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Comments

Graeme_Grant 20-Feb-17 3:10am

Where are the classes that you are mapping the XML against?

ÂĦmâd Ŝâlâĥ 20-Feb-17 4:05am

no problem in class i use select nude also 0 result ,,, but i see the problem here

xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://tempuri.org/"

but how remove this from reader before Deserialize

2 solutions

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Graeme_Grant · Answer 1 · 2017-02-19T21:12:00

Solution 1

This may help you: Convert XML to C# Classes[^]

Posted 19-Feb-17 21:12pm

Graeme_Grant

Comments

ÂĦmâd Ŝâlâĥ 20-Feb-17 4:05am

thanks but the problem here

xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://tempuri.org/"

but how remove this from reader before Deserialize

Graeme_Grant 20-Feb-17 8:28am

You don't remove them, it is handled as part of the deserialization process.

Praneet Nadkar · Answer 2 · 2017-02-20T01:54:00

Hi,

The following code worked for me with your xml:

C#

string xml = "<?xml version=\"1.0\" encoding=\"utf-8\"?><ArrayOfResultInfo xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns=\"http://tempuri.org/\"><ResultInfo><PartNumber>KRPA - 4007 </PartNumber><Manufacturer> test </Manufacturer></ResultInfo></ArrayOfResultInfo>";



           var serializer = new XmlSerializer(typeof(ArrayOfResultInfo));
           ArrayOfResultInfo result;

           using (TextReader reader = new StringReader(xml))
           {
               result = (ArrayOfResultInfo)serializer.Deserialize(reader);
           }

           Console.WriteLine(result.ResultInfo.Manufacturer);
           Console.WriteLine(result.ResultInfo.PartNumber);

           Console.ReadLine();

The classes for xml are as follows:

C#

[XmlRoot(ElementName = "ResultInfo", Namespace = "http://tempuri.org/")]
public class ResultInfo
{
    [XmlElement(ElementName = "PartNumber", Namespace = "http://tempuri.org/")]
    public string PartNumber { get; set; }
    [XmlElement(ElementName = "Manufacturer", Namespace = "http://tempuri.org/")]
    public string Manufacturer { get; set; }
}

[XmlRoot(ElementName = "ArrayOfResultInfo", Namespace = "http://tempuri.org/")]
public class ArrayOfResultInfo
{
    [XmlElement(ElementName = "ResultInfo", Namespace = "http://tempuri.org/")]
    public ResultInfo ResultInfo { get; set; }
    [XmlAttribute(AttributeName = "xsd", Namespace = "http://www.w3.org/2000/xmlns/")]
    public string Xsd { get; set; }
    [XmlAttribute(AttributeName = "xsi", Namespace = "http://www.w3.org/2000/xmlns/")]
    public string Xsi { get; set; }
    [XmlAttribute(AttributeName = "xmlns")]
    public string Xmlns { get; set; }
}

Hope this helps !