How to load content without reloading?

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Hello. As in the title.I would like to write such a 'system'. Someone knows how I can do it? I don't know how I can use Ajax. Please somebody help me. Okay to the point.
I want send data to addcomment.php

PHP

<form method="post" action="addcomment.php">
<input type="hidden" name="nick" id="nick_ajax" value="'.$_SESSION['user'].'" />
<input type="text"id="content_ajax" placeholder="Write a comment..." name="content" />
<input type="hidden" name="id" id="id_content_ajax" value="'.$article['id'].'" />
<input type="submit" id="o_sl" name="sent" value="Send" />
</form>

Script addcomment.php

PHP

<?php
	require_once('config/config.php');
	if($_POST['sent']){
		$nick = $_POST['nick'];
		$content = $_POST['content'];
		$postID = $_POST['id'];
		
		$sql_comment = $PDO->prepare('insert into `comments` (`nick`,`content`,`postID`) values (:nick,:content,:id)');
		$sql_comment->execute(array(':nick' => $nick, ':content' => $content, ':id' => $postID));
		header('Location: home.php?success');
	}
	else {
		header('Location: home.php?fail');
		die();
	}
?>

What I have tried:

JavaScript

$(function() {
     $("#o_sl").click(function() {
     var nick_ajax = $('#nick_ajax').val();
     var content_ajax = $('#content_ajax').val();
     var id_content_ajax = $('#id_content_ajax').val();
     var dataString = '&nick='+ nick_ajax + '&content=' + content_ajax +'&id=' +id_content_ajax;

     $.ajax({
         type: 'POST',
         url: 'add_comment.php',
         data: dataString,
         success: function(data) {
             if( data == '0' )
                 alert( 'Error' );
             else
                 window.location = window.location;
         }
     });
     });
 });

Posted 14-May-17 8:30am

Mike CJ

Updated 15-May-17 0:40am

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W∴ Balboos, *GHB* · Answer 1 · 2017-05-15T00:40:00

Solution 1

Here's where I learned to do it. AJAX Introduction[^]

Once I got used to the idea I almost never use forms (and thus go to a new page) - just update what I have. If you can master this and extend it, afterward, to something like JSON, you'll be very glad you did.

Posted 15-May-17 0:40am

W∴ Balboos, GHB

Comments

Mike CJ 15-May-17 10:59am

Okay. So how I can add other variable ?
I have now this code:
$(document).ready(function(){
$('#button').on("click",function(){
var postid = $(this).attr('id');
$.ajax({
url:'comment_post.php',
type: 'post',
data:{'postid': postid
}
});

W∴ Balboos, GHB 15-May-17 11:48am

The link tells you how ajax is done
As far as jQuery goes . . . I don't use it.

You'll need to put in some effort, here, either to learn to use javaScript/AJAX or stick with your jQuery and hope for someone to help with that.

Mike CJ 15-May-17 12:13pm

This is very difficult, but fine now I have to learn it.