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Python
def cube(number):
    return number**3
    
def by_three(number):
    if number%3==0:
        cube()
        return cube.
    else:
        return False


What I have tried:

I need to create a function which cubes a given number. then i have to create another function called by_three which checks if its divisible by three. if it is then i have to cube it through the first function else return false. im a newbie and started coding just a couple of days ago.I have no idea what is wrong with my code
Posted
Updated 25-Jun-17 16:40pm
v2

1 solution

Advice: follow tutorials to learn the basics of python.
You probably got error messages
Python
def cube(number):
    return number**3
    
def by_three(number):
    if number%3==0:
        # you forgot to tell what you cube()
        cube()
        # here, cube is a variable that does not exist
        # the '.' at the end does not exist
        return cube.
    else:
        return False


There is a tool that allow you to see what your code is doing, its name is debugger. It is also a great learning tool because it show you reality and you can see which expectation match reality.
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.

Debugger - Wikipedia, the free encyclopedia[^]
27.3. pdb — The Python Debugger — Python 3.6.1 documentation[^]
Debugging in Python | Python Conquers The Universe[^]
pdb – Interactive Debugger - Python Module of the Week[^]
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.
 
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Comments
lordsenbonzakura 26-Jun-17 10:12am    
could you please upload the correct code?It will be really helpful

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