Need help with a C program exercise

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Given an Int input , find the sum of the individual number in the input.
Eg.

Please input number : 12345 <-- user input
1+2+3+4+5=15 <---output

What I have tried:

Problem #2
Now, whenever I have an input that ends or starts with a 0 it doesn't print it out.
eg. Please input number: 100
output: 1=1

Problem #1(Solved)
So I was able to write out the equations I need to get the sum of the numbers.

C++

while (input != 0)
   { 
      remainder = input % 10; 
      input = input / 10;
      sum = sum + remainder; }

However I cant figure out the logic behind printing it out, so that it shows 1+2+3.
(Solved, able to produce 1+2+3=6 output Thanks!)

C++

while (input!= 0)
   { 
      remainder = input% 10; 
      input= input/ 10;
	  sum       = sum + remainder;
       
	if(digits !=0)
	 { printf("+");}
     printf("%d", remainder);
	 digits++;	 
 
   }

Posted 7-Oct-17 1:45am

Crulas

Updated 7-Oct-17 3:57am

Patrice T

v5

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2 solutions

Solution 2

Quote:
However I cant figure out the logic behind printing it out , so that it shows 1+2+3.

You have a few options:
- Store digits in a list as you are doing the slicing and sum and print them later as they came in reverse order.
- Build a string as you are doing the slicing and sum. "" > "5" > "4+5" > "3+4+5"
- convert input to string, then print chars 1 by 1 and insert '+'s as you do so.

Posted 7-Oct-17 3:46am

Patrice T

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OriginalGriff · Accepted Answer · 2017-10-07T02:09:00

It's a little complicated, because of the need to print "+" characters between them.
So add a counter:

C++

int digitCount = 0;

Inside the loop, check the counter and print the "+" if you need it:

C++

if (digitCounter != 0)
   {
   printf("+");
   }
digitCounter++;

Then still inside the loop print each digit:

C++

printf("%d", remainder);

After the loop, print the "=" and the sum.