Why the value changes

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1.00/5 (1 vote)

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C

#include<stdio.h>
#include<conio.h>
void main()
{
int a=16,b=012,c=054;
printf("a=%d b=%d c=%d",a,b,c);

}

What I have tried:

why the output changes what is the conversion...

Posted 23-Oct-17 19:37pm

Dinesh Sahoo

Updated 23-Oct-17 20:59pm

CPallini

v2

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OriginalGriff · Accepted Answer · 2017-10-23T19:51:00

When you prefix a number with 0 in C it assumes that the number you are inputting is no long in decimal (base 10, the one we normally use in the real world) but instead in octal (base 8, it runs 0, 1, ... 7, 10, 11, ... 17, 20, 21, ...)
So this:

int a=16,b=012,c=054;

Creates three variables and assignes values to them:

a    16   deciml, value 16
b   012   octal,  value 10 in decimal
c   054   octal,  value 44 in decimal

You can also prefix number with "0x" or "0X" to enter hexadecimal (or just "hex") numbers
- which are a lot more common these days than octal.

See here: Octal - Wikipedia[^]
And here: Hexadecimal - Wikipedia[^]