Why this code not giving lcm of two numbers ?

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Keeping aside how we calculate lcm by gcd/(a*b) way, how to modify this code slightly such that it gives ad-hoc result for lcm calculation.

What I have tried:

void main()
{
	int a,b,i,v,lcm=1;
	printf("Enter two numbers");
	scanf("%d %d",&a,&b);
    
    	
	while(i<=(a*b))
	{
		if( a%i==0 && b%i==0)
		{
			v= i*lcm;
			i++;
			
		}
		else
		i++;
	
	}
	printf("The lcm is %d",v);
	getch();
}

Posted 13-Nov-17 23:47pm

Member 11980555

Updated 14-Nov-17 0:11am

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Richard MacCutchan 14-Nov-17 6:05am

What formula are you trying to use? Also, you have not initialised i before using it in your while loop.

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CPallini · Answer 1 · 2017-11-14T00:11:00

Try

C

#include <stdio.h>

int main()
{
  int a,b,lcm;
  printf("Enter two numbers\n");
  scanf("%d %d",&a,&b);


  lcm = a > b ? a : b;

  while(lcm <= (a*b) )
  {
    if( lcm%a==0 && lcm%b==0)
    {
      break;
    }
    ++lcm;
  }
  printf("The lcm is %d\n",lcm);
  getchar();
  return 0;
}