Input submit onlick and onserverclick not working

Question

0.00/5 (No votes)

See more:

Hi

I'm working on a simple login screen with the below code:

<form id="login">
    <div class="formHeader">
      <h1>Login</h1>
    </div>
    <div class="formDiv">
      <input type="text" placeholder="Email" name="txtEmail"/>
      <div class="inputImage fa fa-user"></div>
    </div>
    <div class="formDiv">
      <input type="password" placeholder="Password" name="txtPassword"/>
      <div class="inputImage fa fa-lock"></div>
    </div>
    <div class="formDiv">
      <label id="remember">
        <input type="checkbox" name="cbxRemberMe" value="Checked"/>
        <div class="checkbox"></div><span>Remember me</span>
      </label>
    </div>
    <div class="formDiv">
      <input type="submit" value="LOGIN" runat="server" onserverclick="btnLogin_Click" onclick="btnLogin_Click" />
    </div>
    <div class="formFooter"><a class="forgot" href="#">Forgot Password</a></div>
  </form>

and back-end code

 protected void btnLogin_Click(object sender, EventArgs e) 
{

}

But the button does not call the backend code at all.

Nothing happens except the URL changes from
"http://localhost:15726/Pages/Login.aspx" to
"http://localhost:15726/Pages/Login.aspx?txtEmail=&txtPassword=&ctl00=LOGIN"

I cannot put a Runat=Server attribute in the form as I have 2 forms on this page (login and register)

any help is appreciated.

What I have tried:

1. Playing around with Runat=Server, onclick() and OnServerClick() (swapping around and changing them up)

2. Making input type=submit / input type=button

none of these work.

Posted 22-Feb-18 3:09am

Member 9374423

Updated 22-Feb-18 3:26am

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

F-ES Sitecore · Answer 1 · 2018-02-22T03:27:00

The url is updating like that because you don't have POST as the form method

<form id="login" method="POST">

However that isn't your main problem. You can have multiple forms on the page if you need to, they just can't be nested and only one can have runat=server. If your forms are not nested then you can use a normal form but you won't be able to use server-side functionality like you do with asp controls. Instead you'll need to use the page_load event and use Request.Form["controlNameHere"] to analyse the values of your form components (note it is the control's name, not the id you use to reference the control).

If your forms *are* nested then you need to get rid of all but the outer form and wrap your inner group of login controls in an asp:Panel and specify the "DefaultButton" attribute of the panel

<asp:Panel DefaultButton="btnLogin" runat="server">
    <asp:TextBox ID="txtUsername" runat="server" />
    <asp:Button ID="btnLogin" Text="Login" runat="server" />
</asp:Panel>

That creates a kind of virtual form-within-a-form where if someone presses RETURN on the username box then it will click the Login button allowing you to use btnLogin_Click. This will cause a postback containing the entire form but you just ignore the controls you're not interested in.

So to sum up either use a non-nested non-server form and use Request.Form to read the values from the form elements, or have one server form that has all controls and use Panel\DefaultButton to create a form within a form.