How can I make an array of linked lists that are implemented using cursor implementation?

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i have the cursor implementation of linked lists in c language and i need to make an array of linked lists using cursor implementation as i need this array to implement radix sort for strings

What I have tried:

typedef int PtrToNode; // simulates the idea of a pointer
typedef PtrToNode List; //simulates struct List
typedef PtrToNode Position; //simulates node*

typedef struct{
 char Element[50];
 Position Next; //simulates node * next
}Node;

///1. Create an array of pointer of node type
Node* buckets[27];

///function of radix sort that should have the array of linked lists

void Radix_Sort( char names[5][5],int max){
int i,j;

///1.initialize buckets
for(i=0;i<27;i++){
        buckets[i]=NULL;
}

///.2

    
 }   



}

Posted 6-Apr-18 5:50am

Member 13766236

Updated 6-Apr-18 23:00pm

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OriginalGriff 6-Apr-18 11:53am

And?
What have you tried?
Where are you stuck?
What help do you need?

Member 13766236 6-Apr-18 12:06pm

I am stucked in how to make and initialize this array of cursor

Rick York 6-Apr-18 12:48pm

You keep using the word "cursor" - what does any of this have to do with a cursor?

Anyway, look at the column titled "Related Questions" on the right. Someone asked practically the same question about their homework several years ago. You might find the discussion helpful.

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KarstenK · Accepted Answer · 2018-04-06T23:02:00

You must understand the concept of linked lists and cursors and use pointers. The cursor is only the pointer to the actual element. See also head and tail.

In the article How to create Linked list using C/C++ all is described, so read and understand the whole article.

C++

typedef struct Node{
 char text[50];
 Node* next; //used as a pointer to next node * next
};

Node *node1 = new Node;//allocate memory 
strcpy(node1->text, "This is node 1");
//
Node *node2 = new Node;
strcpy(node1->text, "This is node 2");
node2->next = node1;//link them