Get XML from SQL without nested nodes

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Hi,
Using the following query, I get a result which has 'sub'-node containing multiple 'sub'-nodes and a 'unrelated' node also containing 'unrelated'-nodes.
How can I get the result without the outer 'sub' and 'unrelated' nodes?

The query is made up but reflects a real life query I'm using which must produce a pre-existing result as described.

<master>
  <alldata head_id="C6DF494E-4DA7-4726-8288-BB463CB96834">
    <sub>
      <sub>
        <own_id>10</own_id>
        <own_field>Sub1 field</own_field>
      </sub>
      <sub>
        <own_id>11</own_id>
        <own_field>Sub2 field</own_field>
      </sub>
    </sub>
    <unrelated>
      <unrelated>
        <own_id>100</own_id>
        <own_field>another field</own_field>
      </unrelated>
    </unrelated>
  </alldata>
</master>

What I have tried:

declare @head1  table<br />
(head_id uniqueidentifier)<br />
<br />
declare @sub1 table (<br />
head_id uniqueidentifier,<br />
own_id int,<br />
own_field nvarchar(20))<br />
<br />
declare @sub2 table (<br />
head_id uniqueidentifier,<br />
own_id int,<br />
own_field nvarchar(20))<br />
<br />
declare @unrelated table (<br />
head_id uniqueidentifier,<br />
own_id int,<br />
own_field nvarchar(20))<br />
<br />
declare @gd uniqueidentifier;<br />
set @gd = newid();<br />
<br />
insert into @head1 (head_id) values (@gd)<br />
insert into @sub1 (head_id,own_id,own_field) values (@gd,10,'Sub1 field')<br />
insert into @sub2 (head_id,own_id,own_field) values (@gd,11,'Sub2 field')<br />
insert into @unrelated (head_id,own_id,own_field) values (@gd,100,'another field')<br />
<br />
<br />
select alldata.* from<br />
    (select head.head_id<br />
        ,(<br />
            select * from <br />
                (<br />
                    select sub1.own_id,sub1.own_field <br />
                        from @sub1 sub1 <br />
                        where sub1.head_id = head.head_id<br />
                        union all <br />
                    select sub2.own_id,sub2.own_field <br />
                        from @sub2 sub2 <br />
                        where sub2.head_id = head.head_id<br />
                ) tmp for xml path('sub'), type ) sub<br />
<br />
        ,(select unrelated.own_id,unrelated.own_field <br />
            from @unrelated unrelated where unrelated.head_id = head.head_id <br />
            for xml path('unrelated'),type <br />
            ) unrelated<br />
        from @head1 head <br />
        ) alldata for xml auto,root('master')

Posted 24-Jun-18 20:22pm

Member 10282167

Updated 26-Jun-18 4:03am

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Member 10282167 · Answer 1 · 2018-06-26T04:04:00

For those interested, solution consisted of putting the union query into a CTE.

declare @head1  table
(head_id uniqueidentifier)

declare @sub1 table (
head_id uniqueidentifier,
own_id int,
own_field nvarchar(20))

declare @sub2 table (
head_id uniqueidentifier,
own_id int,
own_field nvarchar(20))

declare @unrelated table (
head_id uniqueidentifier,
own_id int,
own_field nvarchar(20))

declare @gd uniqueidentifier;
set @gd = newid();

insert into @head1 (head_id) values (@gd)
insert into @sub1 (head_id,own_id,own_field) values (@gd,10,'Sub1 field')
insert into @sub2 (head_id,own_id,own_field) values (@gd,11,'Sub2 field')
insert into @unrelated (head_id,own_id,own_field) values (@gd,100,'another field');


with subs (head_id,own_id,own_field)
as 
( select sub1.head_id,sub1.own_id,sub1.own_field 
    from @sub1 sub1 
    union all 
    select sub2.head_id,sub2.own_id,sub2.own_field 
    from @sub2 sub2 
)

select head.head_id
  ,( select * from subs where subs.head_id = head.head_id for xml path('sub'),type )


  ,(select unrelated.own_id,unrelated.own_field 
    from @unrelated unrelated where unrelated.head_id = head.head_id 
  for xml path('unrelated'),type )
  from @head1 head 
  for xml auto,root('master')

Kudos to https://www.sqlservercentral.com/Forums/Users/Eirikur-Eiriksson