I have use the parallel.invoke method and in which 2 method are present which increment the common variable but it is not increment the variable

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I have use the parallel.invoke method and in which 2 method are present which increment the common variable.

int cnt=0;

parallel.invoke(
()=>method1,
()=>method2
);

public void method1()
{
cnt++;
}
public void method2()
{
cnt++;
}

What I have tried:

I have use the Volatile for variable
I have used Interlocked.increment but not able to resolve

Posted 4-Jul-18 4:35am

Member 12893295

Updated 4-Jul-18 5:21am

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OriginalGriff · Accepted Answer · 2018-07-04T05:21:00

When you show us code, show us what you actually tried - that wont; compile for a large pile of reasons!

The most likely reason it doesn't work is that cnt is a local variable to the method in which you are calling Parallel.Invoke.
If you correct your compiler errors (and add some logging statements) it works just fine:

namespace GeneralTestingConsole
    {
    class SampleClass
        {
        static int cnt = 0;
        public static void Main()
            {

            Parallel.Invoke(
            () => method1(),
            () => method2()
            );
            Console.WriteLine(cnt);
            }

        public static void method1()
            {
            Console.WriteLine("1:{0}", cnt);
            cnt++;
            Console.WriteLine("1={0}", cnt);
            }
        public static void method2()
            {
            Console.WriteLine("2:{0}", cnt);
            cnt++;
            Console.WriteLine("2={0}", cnt);
            }
        }
    }

1:0
2:0
2=2
1=1
2