Click here to Skip to main content
15,891,033 members
Please Sign up or sign in to vote.
0.00/5 (No votes)
See more:
in loop replace name to value. but i want that if 2nd value is null then leave loop without replace 1st value.

What I have tried:

SQL
OPEN TESTPRO;
   LOOP_TESTPRO:loop
   fetch TESTPRO into C_PHD_TAG, C_PHD_MODE;
   if (NOT_FOUND=1 and tagval_not_found=1) then leave LOOP_TESTPRO;
   end if;
	 begin 
   
        set tagval=tagvalue(C_PHD_TAG, CPARAMETER_ID ,c_phd_mode  , v_start_shift_time ,  v_end_shift_time);
        select tagval, C_PHD_TAG;
        
        IF (tagval IS NULL ) THEN 
        SET tagval_not_found=1;
        END IF;        
        
        set replacevalue= REPLACE(upper(formula),upper(C_PHD_TAG), tagval);
         select replacevalue;
             
         set tagval = null;
	 end;
   end loop;
   close TESTPRO;
Posted
Updated 7-Aug-18 21:21pm
v2

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)



CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900