Java.lang.arrayindexoutofboundsexception:3 error in java compilation

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Java

Hello, I am trying to sort 2d array program using bubble sort but when I compile the program, it runs to the specific part of the program, It prints out the 2d array, But, when it reaches to the sorting part, I get an error, "java.lang.Arrayindexoutofboundsexception:3". Please tell me how to get rid of this error. See the code below.

What I have tried:

import java.util.Random;
import java.util.Scanner;

public class arrays {

	public static void main(String[] args) {
		
		Random ran= new Random();
	
		Scanner scan = new Scanner(System.in);
		
		int num,secnum,temp,i,j,k;
		
		System.out.println("Please enter a num.");
		
		
		
		num= scan.nextInt();
		
		System.out.println("Please enter another value.");
		
		secnum = scan.nextInt();
		
		int arrayi[][] = new int[num][secnum];
		
		
		for( i =0; i< num ; i++) {
			
			for( j =0; j< secnum; j++) {
				
				arrayi[i][j]= ran.nextInt(100);
				
			}
		}
		
		System.out.println("The array is below:");
		
for(i =0; i< num ; i++) {
			
			for( j =0; j< secnum; j++) {
				
				System.out.print(arrayi[i][j] + " ");
				
			}
			System.out.println();
		}
for( i =0; i< num ; i++) {
	
	for( j =0; j< secnum; j++) {
		
	for( k=0; k <secnum; k++) {
		if(arrayi[i][k] > arrayi[i][k+1] ) {
			temp = arrayi[i][k];
			arrayi[i][k] = arrayi[i][k+1];
			arrayi[i][k+1] = temp;
		}
	}
		
	}
	
}
System.out.println("Sorted array is below:");
for( i =0; i< num ; i++) {
	
	for( j =0; j< secnum; j++) {
		
		System.out.print(arrayi[i][j] + " ");
		
	}
	System.out.println();
}
		
scan.close();
	}
	

}