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C++
#include <iostream>
using namespace std;

int main()
{
    if (sizeof(int) > -1)
        cout << "Yes";
    else
        cout << "No";
    return 0;
}


What I have tried:

according to me the answer should be yes.
ut the correct answer is no.
how is it possibble?
Posted
Updated 8-Dec-18 22:21pm
v2

1 solution

Because the sizeof operator returns an unsigned value. So the compiler then treats -1 also as an unsigned value. The hexadecimal value of -1 is 0xFFFFFFFF or unsigned decimal 4294967295, which of course is much greater than the size of an integer (which is 4 (not 8)). One of the pitfalls of mixing signed and unsigned values in software.
 
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v2
Comments
Prateek Krishna 7-Dec-18 23:35pm    
Thank you Sir !
but size of int is 4 ..
KarstenK 9-Dec-18 4:22am    
assign -1 to an uint and see. :-O
Richard MacCutchan 9-Dec-18 7:55am    
You are correct but it is just the same.

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