Save dialogbox open a 2 times to save file

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3.00/5 (1 vote)

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Hi developers,

I am exporting datagridveiw in csv file, but when I click a save button to save file, the save dialogbox open to times to save file in csv file format .

Please check this code and please help me write them in correct format:

C#

public void DataExport()
      {
          try
          {

              string strColumn = string.Empty;
              string strRow = string.Empty;
              StringBuilder objSB = new StringBuilder();

              for (int i = 0; i < DGV.Columns.Count; i++)
              {
                  strColumn += (i >= DGV.Columns.Count - 1) ? DGV.Columns[i].Name : DGV.Columns[i].Name + ",";
              }

              objSB.AppendLine(strColumn);

              for (int i = 1; i < DGV.Rows.Count - 1; i++)
              {
                  for (int j = 0; j < DGV.Columns.Count; j++)
                  {
                      strRow += (j >= DGV.Columns.Count - 1) ? DGV.Rows[i].Cells[j].Value.ToString().Replace("\n","";) : DGV.Rows[i].Cells[j].Value.ToString().Replace("\n","") + ",";
                  }
                  objSB.AppendLine(strRow);
                  strRow = string.Empty;
              }

              File.AppendAllText(Locations.Text, objSB.ToString());
              DGV.Refresh();
              MessageBox.Show("File Created.");
          }
          catch (System.Exception ex)
          {
              MessageBox.Show(ex.Message);
          }

      }
public void save_Click(object sender, EventArgs e)
      {
            
          try
          {
              SaveFileDialog SaveDialogbox = new SaveFileDialog();
              SaveDialogbox.FileName = Locations.Text;
              SaveDialogbox.Filter = "Text and CSV Files(*.txt, *.csv)|*.txt;*.csv|Text Files(*.txt)|*.txt|CSV Files(*.csv)|*.csv|All Files(*.*)|*.*";
              SaveDialogbox.FilterIndex = 1;
              SaveDialogbox.RestoreDirectory = true;
              DialogResult Dialogresult1 = SaveDialogbox.ShowDialog();
              if (SaveDialogbox.ShowDialog()==DialogResult.OK)
              {
                  //Locations.Text = SaveDialogbox.FileName;
                  DataExport();
                  Application.DoEvents();
              }     public void save_Click(object sender, EventArgs e)
      {
            
          try
          {
              SaveFileDialog SaveDialogbox = new SaveFileDialog();
              SaveDialogbox.FileName = Locations.Text;
              SaveDialogbox.Filter = "Text and CSV Files(*.txt, *.csv)|*.txt;*.csv|Text Files(*.txt)|*.txt|CSV Files(*.csv)|*.csv|All Files(*.*)|*.*";
              SaveDialogbox.FilterIndex = 1;
              SaveDialogbox.RestoreDirectory = true;
              DialogResult Dialogresult1 = SaveDialogbox.ShowDialog();
              if (SaveDialogbox.ShowDialog()==DialogResult.OK)
              {
                  //Locations.Text = SaveDialogbox.FileName;
                  DataExport();
                  Application.DoEvents();
              }
else 
{
messagebox.show("save process failed");
}
}
           catch (System.Exception ex)
           {
               MessageBox.Show(ex.Message);
           }

       }

Posted 18-Nov-10 18:38pm

vishu1999a

Updated 18-Nov-10 21:29pm

Dalek Dave

v5

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Dalek Dave 19-Nov-10 3:29am

Edited for Grammar and Syntax.

2 solutions

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Not Active · Answer 1 · 2010-11-18T18:48:00

Solution 1

Of course the dialog is opening twice, you have duplicate code in the save_Click method :rolleyes: Are you sure you've posted it correctly?

Posted 18-Nov-10 18:48pm

Not Active

Updated 18-Nov-10 18:56pm

v2

RaviRanjanKr · Answer 2 · 2010-11-18T19:26:00

Ya Mark has already detected Problem what you have did while you posting your code which is about pasting duplicate code.

and this is code you use in try catch and the problem is in this code is you invoke ShowDialog() method two times thats why it appear for two times.

SaveFileDialog SaveDialogbox = new SaveFileDialog();
          SaveDialogbox.FileName = Locations.Text;
          SaveDialogbox.Filter = "Text and CSV Files(*.txt, *.csv)|*.txt;*.csv|Text Files(*.txt)|*.txt|CSV Files(*.csv)|*.csv|All Files(*.*)|*.*";
          SaveDialogbox.FilterIndex = 1;
          SaveDialogbox.RestoreDirectory = true;
          DialogResult Dialogresult1 = SaveDialogbox.ShowDialog();
          if (SaveDialogbox.ShowDialog()==DialogResult.OK)
          {
              //Locations.Text = SaveDialogbox.FileName;
              DataExport();
              Application.DoEvents();
          }

Remove this one

DialogResult Dialogresult1 = SaveDialogbox.ShowDialog();