How to Copy Items from one ListView to Another in C#

If the two listviews are in different solutions, then you cannot simply copy from one and insert to other. I suggest getting all listviewitems to a List<ListviewItem> in one solution project, serialize it, and then:
a. If client and server runs on the same machine, save the serialized List to physical drive in one app, and open in other (monitor the folder for changes and if new file is saved or an existing one is updated, deserialize the file and insert them to target listview)
b. If client and server runs on different machines, send the serialized byte array to target by socketing

For using remoting with c#
In this example create a class library and add the following code. My project name is RemotableObject. Note your project name because you need to refer this in your client and server projects

[Serializable]
public  class Remotable : MarshalByRefObject
{
    public static Delegate setListView;

    public  void Test(ArrayList list)
    {
        object[] args = new object[1];
        args[0] = list;
        setListView.DynamicInvoke(args);

    }

}

Compile this class library in to the dll file.
Now create a server project, add a listview (say listview1) in the form (simple listview for this example, no sublist).
Add refernce to the dll file created.The namespce for my example is using RemotableObject;

You need to add also the System.Runtime.Remoting (Add reference-> in the .Net tab select this and click ok)

Add a button and in the button's click event...

private void button1_Click(object sender, EventArgs e)
{
    try
    {
        ChannelServices.RegisterChannel(new TcpChannel(), false);
    }
    catch { }

    Type requiredType = typeof(Remotable);

    //Relapce the local host to network ip incase the client runs at a network machine, or other remote server name
    // where the configured port is open and ACESSIBLE, not restricted by firewalls and other stuff
    Remotable remoteObject = (Remotable)Activator.GetObject(requiredType, "tcp://localhost:9998/ListService");

    ArrayList list = new ArrayList();
    foreach (ListViewItem item in listView1.Items)
    {
        list.Add(item.Text);
    }
    remoteObject.Test(list);
    remoteObject = null;
}

Note: use these additional libraries for server and as well as for client
using System.Collections;
using System.Runtime.Remoting;
using System.Runtime.Remoting.Channels;
using System.Runtime.Remoting.Channels.Tcp;
using RemotableObject;

In the client form add a list view anf have the following code

You need to add also the System.Runtime.Remoting (Add reference-> in the .Net tab select this and click ok)

Add the reference to the dll to this project as well and have the above references..

public partial class Form1 : Form
{
    private delegate void setList(ArrayList list);
    private ArrayList list;
    public Form1()
    {
        InitializeComponent();
    }

    private void Form1_Load(object sender, EventArgs e)
    {
        TcpChannel tcpChannel = new TcpChannel(9998);
        ChannelServices.RegisterChannel(tcpChannel, false);
        Type commonInterfaceType = typeof(Remotable);

        RemotingConfiguration.RegisterWellKnownServiceType(commonInterfaceType,
        "ListService", WellKnownObjectMode.SingleCall);
        Remotable.setListView = new setList(setListView);

    }

    public void setListView(ArrayList list)
    {
        this.list = list;
        if (listView1.InvokeRequired)
        {
            listView1.Invoke(new MethodInvoker(invoker));
        }
    }

    public void invoker()
    {
        foreach (String listItemText in this.list)
        {
            ListViewItem item = new ListViewItem(listItemText);
            listView1.Items.Add(item);
        }
        listView1.Refresh();

    }
}

;
START the client first, because client listens and server access it execute its method to update the listview.
Then run the server....
click the button (we added earlier) which has the remoting code at its event. Now you can see the listview in the client get updated