OS Determine code for vb.net

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VB

hi all
i need a vb.net code to determine if 32 or 64 bit operation is ?

Posted 15-Apr-11 22:01pm

saeid.piran

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2 solutions

Solution 2

Do you only need to know which code is running by the caller: 32- or 64-bit? It this is just this, it's way too simple:

C#

static int HowManyBits {
    get {
        System.IntPtr ptr = System.IntPtr.Zero;
        return System.Runtime.InteropServices.Marshal.SizeOf(ptr) * 8;
    }
}

For example,

C#

static void Main(string[] args) {
    System.Console.WriteLine( string.Format("{0}-bit", HowManyBit) );
}

will output "32-bit" or "64-bit".

Please also see my comment to the Answer by Abhinav.

—SA

Posted 16-Apr-11 9:41am

Sergey Alexandrovich Kryukov

Updated 16-Apr-11 9:46am

v2

Comments

Abhinav S 17-Apr-11 1:14am

Very useful answer. My 5 (and goes into my bookmarks as well).

Sergey Alexandrovich Kryukov 17-Apr-11 1:23am

Thank you very much, Abhinav,
By the way, it simply follows Microsoft documentation of porting between 32 and 64 bits in a most straightforward way, cannot be wrong.

Abhinav S 17-Apr-11 9:41am

You answered it, so unlikely it is wrong anyway. :)

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Abhinav S · Accepted Answer · 2011-04-15T22:04:00

Solution 1

See
http://channel9.msdn.com/Forums/TechOff/410567-C-Detect-32-bit-or-64-bit-OS[^]
http://www.supportforums.net/showthread.php?tid=11587[^].

Posted 15-Apr-11 22:04pm

Abhinav S

Comments

Sergey Alexandrovich Kryukov 16-Apr-11 15:45pm

Abhinav, this is not too bad, my 5, but I think you're trying to answer the wrong question.
Your samples show "what is the version of OS is installed on the machine writing the current code?".

I think the Question really is: "Is the current code 32-bit or 63-bit"? On 64-bit systems, it can be both; 32-bit software can run on WoW64, see http://en.wikipedia.org/wiki/WoW64.
At the same time, it's easier.

Please see my Answer,
--SA

Abhinav S 17-Apr-11 1:15am

Well the OP has made it hard for us to interpret his question. Not sure what he actually wanted.
Thanks for the 5.

Sergey Alexandrovich Kryukov 17-Apr-11 1:25am

Of course. I'm also not 100% sure, but I think my interpretation is most likely correct, and the answer is simple (and useful as you correctly put it :-).
--SA

Abhinav S 17-Apr-11 9:40am

Your answer is surely useful - I will try and use it sometime as well. Thanks.