2 dimensional arrays in C

Question

0.00/5 (No votes)

See more:

Hello frnds! I am having a trouble in dealing with 2 dimensional arrays in C. Following is the design & code I tried for....
1 4 15 7
8 10 2 11
14 3 6 13
12 9 5 _
The last element is space whr the cursor should be placed & whenever the arrow keys are moved the value must be swapped with the space. Like if now left arrow key is pressed, 5 will move to the right & space will replace 5. Likewise for the remaining arrow keys. The getkey() method below gives the scan code for each arrow key.

// PUZZLE
#include<stdio.h>
#include<conio.h>
#include<dos.h>
int main()
{
	int a[4][4]={{1,4,15,7},{8,10,2,11},{14,3,6,13},{12,9,5,}};
	int i,j,cnt=0,key,ukey,dkey,lkey,rkey,x,y;
	int pos,val;
	 int temp;
	clrscr();
	printf("\nFollowing is the puzzle:\n");
	printf("\nUse the arrow keys for solving the puzzle\n---------------------------------------");
	for(i=0;i<4;i++)
	{
	   printf("\n");
	   for(j=0;j<4;j++)
	   {
	      if(i==3 && j==3)
		{
		     a[3][3]=' ';
		     printf("%c",a[3][3]);
		     break;
		}
		printf("%d\t",a[i][j]);
	   }
	}
	//pos=a[4][4];
	if(cnt==0)
	{
	   key=getkey();
	   if(key==77 || key==80) //check for right & down key and do nothing
	   {   }
	   else
	   {
	       i=3;j=3;
	       if(key==72)        //up arrow
	       {
		   // printf("\nYou pressed the %d arrow key",key);
		   temp=a[i][j];
		   a[i][j]=a[i-1][j];
		   a[i-1][j]=temp;		 
		   for(i=0,j=0;i<4,j<4;i++,j++)
		       printf("%d",a[i][j]);
	       }
	       else if(key==75)        //left arrow
	       {
		   //pos=a[i][j];
		   temp=a[i][j];
		   a[i][j]=a[i][j-1];
		   a[i][j-1]=temp;
	       }
	   }//else
	   cnt++;
	}//outer if
	getch();
	return 0;
}
int getkey()
{
	union REGS i,o;
	while(!kbhit())
		;
	i.h.ah=0;
	int86(22,&i,&o);
	return(o.h.ah);
}

Any suggestion will be appreciated. Thanks.

Posted 10-Jul-11 23:30pm

Cool Bhakti

Updated 10-Jul-11 23:32pm

వేంకటనారాయణ(venkatmakam)

v2

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2011-07-11T01:24:00

Firstly, use more sensible names: if you call your variables by names that reflect what they do, it is a lot easier to understand what you are doing. For example, have two variables called userRow and userCol to tell you where the user actually is.
Secondly, use routines to break up your code and make it easier to read:

#include <stdio.h>
#define ROWS_COUNT 4
#define COLS_COUNT 4
#define TRUE (1==1)
int playSurface[ROWS_COUNT][COLS_COUNT]={{1,4,15,7},{8,10,2,11},{14,3,6,13},{12,9,5,-1}};
int userRow = ROWS_COUNT - 1;
int userCol = COLS_COUNT - 1;
int main()
   {
   int key;
   do
      {
      ShowPlaySurface();
      key = GetKey();
      if (key == 'Q' || key == 'q')
         {
         break;
         }
      DoMove(key);
      } while (TRUE);
   exit(0);
   }
int ShowPlaySurface()
   {
   int i, j;
   for (i = 0; i < ROWS_COUNT; i++)
      {
      for (j = 0; j < COLS_COUNT; j++)
         {
         if (i == userRow && j == userCol)
            {
            printf ("\t");
            }
         else
            {
            printf ("%d\t", playSurface[i][j]);
            }
         }
      printf("\n");
      }
   }
   
int GetKey()
   {
   return (int) getch();
   }
int DoMove(int key)
   {
   }

Now, all you have to do is concentrate on the Do Move function - which is just a case of checking keys, and moving in the appropriate direction, if you can. Easy!