manipulating strings with try parse()

Question

1.00/5 (1 vote)

See more:

Hi there, is there some way of returning Zero (0) if int.TryParse() cannot return int

I have two text Boxes which i must check for numeric inputs using int.try Parse()
If one or both of my text Boxes contain strings or nulls other other than int values, i want to set their values to zero (0) and sum up the results

int number1=Convert.ToInt32(textBox1.Text);

int number2=Convert.ToInt32(textBox2.Text);

int sum = number1 + number2;
  
if number1=null  or "string" and number2 = null or "string"

sum=0+0;

Thanks in Advance
Yours Martin

Posted 18-Jul-11 22:09pm

katumbamartin

Updated 18-Jul-11 22:46pm

Toniyo Jackson

v2

Add a Solution

4 solutions

Solution 3

int a = 0;
int b = 0;
int.TryParse(textbox1.Text, out a);
int.TryParse(textbox2.Text, out b);
int sum = a + b;

TryParse will ninja it for you ;)

Posted 18-Jul-11 22:14pm

DominicZA

Comments

Manfred Rudolf Bihy 19-Jul-11 4:38am

Good answer! 5+

Solution 4

Might helps,

C#

class Program
{
    static int ParseInt(string valueToParse)
    {
        int result;
        return int.TryParse(valueToParse, out result) ? result : result;
    }
    static void Main(string[] args)
    {
        int sum = ParseInt("H5") + ParseInt("5");
    }
}

:)

Posted 18-Jul-11 22:23pm

Mohammad A Rahman

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Accepted Answer · 2011-07-18T22:11:00

Solution 1

Try:

int val;
int i = int.TryParse(testBox1.Text, out val) ? val : 0;

Posted 18-Jul-11 22:11pm

OriginalGriff

Comments

Manfred Rudolf Bihy 19-Jul-11 4:37am

Three nearly identical answers. I think I'll have to put my tinfoil hat on again ;).

My 5!

Manfred Rudolf Bihy · Accepted Answer · 2011-07-18T22:14:00

Solution 2

int number1 = (int.TryParse(textBox1.Text, out number1)) ? number1 : 0;
int number2 = (int.TryParse(textBox2.Text, out number2)) ? number2 : 0;
int sum = number1 + number2;

Cheers!

—MRB

Posted 18-Jul-11 22:14pm

Manfred Rudolf Bihy

Comments

Espen Harlinn 19-Jul-11 4:49am

Neat, my 5