Remove secondary axis label

Question

0.00/5 (No votes)

See more:

Hi !

I dinamically add graf from code :

C#

bool gridLine = true;
List<lineseries> list = new List<lineseries>();
for (int i = 0; i < SeriesCount; i++)
{
    list.Add(new LineSeries());
}
foreach (LineSeries series in list)
{
    series.IsSelectionEnabled = true;
    series.IndependentValueBinding = new System.Windows.Data.Binding("Key");
    series.DependentValueBinding = new System.Windows.Data.Binding("Value");

    LinearAxis dependentLA = new LinearAxis();
    dependentLA.Orientation = AxisOrientation.Y;
    dependentLA.Maximum = maximum;
    dependentLA.Minimum = minimum;
    dependentLA.Interval = interval;
    dependentLA.Title = axisYname;
    dependentLA.Location = AxisLocation.Left;
    if (gridLine)
    {
        dependentLA.ShowGridLines = true;
    }
    else
    {
        dependentLA.ShowGridLines = false;
    }
    series.DependentRangeAxis = dependentLA;
    gridLine = false;

    graf.Series.Add(series);
}</lineseries></lineseries>

But it shows chart with two Y axis labels on left side (if Location is auto: one on left, second on the right side). I try to create graf just with one Y axis and 2+ lines.
Any1 help me ?

P.S.: If i define just one LinearAxis (for example in first series), second is generated automatically and it shows two axis Y with labels and with gridlines (it looks terrible). If I define no LinearAxis its good, but i need set range,max,min,..

Posted 20-Nov-11 23:33pm

iamgun10a

Updated 20-Nov-11 23:40pm

v2

Add a Solution

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

iamgun10a · Accepted Answer · 2011-11-21T01:17:00

Finally I have found solution.

{
List<lineseries> list = new List<lineseries>();
for (int i = 0; i < SeriesCount; i++)
{
    list.Add(new LineSeries());
}
LinearAxis dependentLA = new LinearAxis();
dependentLA.Orientation = AxisOrientation.Y;
dependentLA.Maximum = maximum;
dependentLA.Minimum = minimum;
dependentLA.Interval = interval;
dependentLA.Title = axisYname;
dependentLA.Location = AxisLocation.Left;
dependentLA.ShowGridLines=true;

CategoryAxis independentLA = new CategoryAxis();
independentLA.Orientation = AxisOrientation.X;
independentLA.Location = AxisLocation.Bottom;
independentLA.Title = axisXname;

graf.Axes.Add(dependentLA);
graf.Axes.Add(independentLA);


foreach (LineSeries series in list)
{
    series.IsSelectionEnabled = true;
    series.IndependentValueBinding = new System.Windows.Data.Binding("Key");
    series.DependentValueBinding = new System.Windows.Data.Binding("Value");

    graf.Series.Add(series);
}

}</lineseries></lineseries>