how to generate random number in 4 digits..

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Can Anyone help me...

in my coding generating random number upto 3 digits i want from 4 digits.. what can i do for that.... and also it generate 2 times page loading & submit time..but i want only when page is load...ple help me..

coding:

C#

public void securitykey()
   {
       Random randobj = new Random();
       byte[] randArray = new byte[2000];
       randobj.NextBytes(randArray);
       for (int i = 0; i < randArray.Length; i++)
           Label4.Text = randArray[i].ToString();
   }

Posted 21-Dec-11 18:24pm

M.Narmatha

Updated 12-Dec-16 19:56pm

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Sergey Alexandrovich Kryukov 22-Dec-11 1:03am

Why do you think a security key of 4 digits could be enough? Even in hexadecimal digits, this is only a matter of trying no more than 65536 times... (Or gosh, our vulnerable, vulnerable checking accounts :-(
In security, people usually consider 1-2 Kilobytes keys as absolute minimum... How about that?
--SA

2 solutions

Solution 3

how to generate random number 3digits

Posted 12-Dec-16 19:56pm

Member 12901372

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Patrice T 13-Dec-16 4:02am

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Sergey Alexandrovich Kryukov · Accepted Answer · 2011-12-21T19:14:00

First of all, I really cannot understand why so many people do the same bad mistake all the time? The Random object should be created only once (per lifetime of the while application domain). I cannot understand what's the rationale behind that? Don't do it! At least move initialization of randobj out of the loop.

(I also cannot stop be amazed about using sub-string "obj" or "object" in the name of object, "app" or "application" in the name of application, "arr" or "array" in the name of array, etc. How can it even come to one's mind?!)

The object randArray makes no sense, whatsoever. The hard-coded immediate constant is just amazing. And the loop…

Let's say you need four decimal digits. All you need is:

C#

Random random = new Random();
int value = random.Next(10000); //will generate a number 0 to 9999

—SA