Random Number Generation

If your input values are indexed i.e. you can access one value out of it using some index, then use methods in Random class (one which lets you set the upper and the lower limit).

In which format do you have your input values?

To add to the other answers, since you will already have the input numbers you should put them into a collection like a List<T> or Array. Then generate a random number using Random.Next(int) that is bound by 0 and the size of your collection minus 1. Use the result as an index for your collection. The code should look something like this:

double GetRandomElement(IList<double> items, Random rand)
{   
   int index = rand.Next((int)(items.Count()-1));
   return items[index];
}

You should be able to send an Array or List<T> to this method.

Hi,

Please see the following code to generate random number in C#.

Random RandomValue = new Random();<br />
       int value = RandomValue.Next(10000, 1000000);

Note:RandomValue.Next(10000, 1000000); contains two arhument one is Lower Limit and other is Upper Limit.
for the above example it will generate random number between 10000 to 1000000.

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Thanks & Regards,
Imdadhusen

use this and you will get the desired result

<br />
Random rand = new Random();<br />
<br />
Response.Write(rand.Next(0, 10)); <br />

where in rand.next("lower value","upper value")