Need Json method to return a View or PartialView,...

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Hi frnds can any one please advice me a solution to my problem,...

i'm working on mvc3 razor apps,

i have myaccount details page which consists of different blocks of details like,

Name: under this block, first name, last name
address: address 1,2,city state, zip,...
license: number,expiry,issue country..

so whenever i edit any block i don't want page to getting refresh,so using jquery, ajax and json methods but, my problem is

C#

[JsonException]
      public JsonResult AccountDetailsUpdate(MyDetailsModel mydetailsmodel)
      {
        return View("viewname");
      }

but it throws me error, unable to convert JsonResult to ViewResult
i want to return to a view from json method, how can we make it

Posted 1-Feb-12 3:04am

m19anand

Updated 1-Feb-12 3:40am

v2

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Christian Graus · Answer 1 · 2012-02-01T08:02:00

Solution 1

You're returning a view. That is not a JsonResult. The error is telling you to return Json, because you said you would. This[^] shows how to return Json, the short version is

return Json(xxx)

where xxx can be a list, I usually end up returning an anonymous class like return Json(new { MyResult = true, MyValue = myVar } );, etc.

Posted 1-Feb-12 8:02am

Christian Graus

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m19anand 2-Feb-12 2:49am

Hi Christian Graus,

thanks for ur response, but actually my problem is that only, from this json method i should navigate to a particular view so I mentioned "Return View()" instead of Json(), cant i redirect a json method to a View...??? please say the solution to navigate to a view from this json method