Group similar items and store the maximum date

Question

0.00/5 (No votes)

See more:

Hi Guys,

I have a table containing different materials masses and round numbers over different periods of the day. Samples are taken at all different times.
Basically I would like to add the sample analysis for similiar rounds together, and display however the latest sample date.

To illustrate:

Table:

Date_Time Round No Batch_Mass

17/02/2012 15:42:35 16 500
17/02/2012 15:38:35 16 400
17/02/2012 15:33:35 15 200

The correct output would be:

Date_Time Round No Batch_Mass

17/02/2012 15:42:35 16 900
17/02/2012 15:33:35 15 200

Basically, the latest time for round number 16 was 17/02/2012 15:42:35 and the cumulative mass was 900

Thanks Guys!!

Posted 16-Feb-12 20:30pm

JoneSleeve

Add a Solution

2 solutions

Solution 2

Dear Varun,

Thank you for the answer.

I have tried using this , initially it did not exactly work, but i just used the max sample_date and it worked perfectly.

SQL

SELECT  ROUND_NUMBER,sum(BATCH) as total, max(sample_date) as latest
FROM test
GROUP BY round_number;

ROUND_NUMBER TOTAL LATEST
---------------------- ---------------------- -------------------------

16 900 2012-02-17 09:02:43
15 200 2012-02-17 08:02:14

Thanks..

Posted 16-Feb-12 21:15pm

JoneSleeve

Comments

Varun Sareen 17-Feb-12 4:33am

thanks

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Varun Sareen · Accepted Answer · 2012-02-16T20:53:00

Solution 1

Dear Friend,

Apply the group by clause on the round number it will bring the result you require.

http://www.tizag.com/sqlTutorial/sqlgroupby.php[^]

Thanks

Posted 16-Feb-12 20:53pm

Varun Sareen