Upload file in each row of asp.net gridview

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Hi,

I need to select file from disk in each row of datagrid. I am using FileUpload as following but its not accessable

C#

fu = (FileUpload)row.FindControl("fu_doc");

on server side.

C#

<asp:TemplateField HeaderText="Select file">
 <itemtemplate>
   <asp:FileUpload ID="fu_doc"; runat="server"> 
 </itemtemplate>

Any suggestion?

Posted 14-Mar-12 21:16pm

JustShahzad

Updated 14-Mar-12 21:20pm

member60

v2

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member60 · Answer 1 · 2012-03-14T21:31:00

try:

XML

  <asp:TemplateField HeaderText="Logo Upload">
    <ItemTemplate>
        <asp:FileUpload ID="FileUpload4" runat="server" /><asp:Button ID="bt_upload" runat="server" EnableViewState="False" Text="Upload" CommandName="Upload" />
</ItemTemplate>
</asp:TemplateField>

and in the serverside:

C#

protected void GridView1_RowCommand(object sender, GridViewCommandEventArgs e)
   {
       Button bts = e.CommandSource as Button;
       Response.Write(bts.Parent.Parent.GetType().ToString());
       if (e.CommandName.ToLower() != "upload")
       {
           return;
       }
       FileUpload fu = bts.FindControl("FileUpload4") as FileUpload;//here
       if (fu.HasFile)
       {
           bool upload = true;
           string fleUpload = Path.GetExtension(fu.FileName.ToString());
           if (fleUpload.Trim().ToLower() == ".xls" | fleUpload.Trim().ToLower() == ".xlsx")
           {
               fu.SaveAs(Server.MapPath("~/UpLoadPath/" + fu.FileName.ToString()));
               string uploadedFile = (Server.MapPath("~/UpLoadPath/" + fu.FileName.ToString()));
               //Someting to do?...
           }
           else
           {
               upload = false;
               // Something to do?...
           }
           if (upload)
           {
               // somthing to do?...
           }
       }
       else
       {
           //Something to do?...
       }
   }

modify according to your requirement