multi checkbox columns in gridview

Question

0.00/5 (No votes)

See more:

hi everybody, im new here and a dont have the best inglish, I will do my best to make me understand

now, i have a litle problem with my gridview.
im trying to put 4 columns with checkboxs into my grdiview, each colum has a unique checkbox in the header and im try to make that header checkbox a "selectAll checkbox"... 1 for each colum

i have this code in the first checkbox colum.. when i select this checkbox, each checkbox in every colum was checked, what can i do?

JavaScript

 <script language="javascript" type="text/javascript">
       function SelectAll(Id) {
           var myform = document.forms[0];
           var len = myform.elements.length;

           document.getElementById(Id).checked == true ? document.getElementById(Id).checked = false : document.getElementById(Id).checked = true;

           for (var i = 0; i < len; i++) {
               if (myform.elements[i].type == 'checkbox') {
                   if (myform.elements[i].checked) {
                       myform.elements[i].checked = false;
                   }
                   else {
                       myform.elements[i].checked = true;
                   }
               }
           }
       }
</script>

Posted 20-Mar-12 11:42am

FelipeVazquez

Add a Solution

Comments

Karthik. A 20-Mar-12 20:53pm

For such tasks, jquery is the way to go! I am not saying you should not do this in pure javascript, but in case you need a solution for this in jquery you would really get a lot of answers, me included! if you are unaware of jquery, have a look at it!

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Nilesh Patil Kolhapur · Answer 1 · 2012-03-20T19:01:00

hey
try this.

C#

function CheckAll(checkboxId, index) {
            var grid = document.getElementById('GridView1');

            if (grid.rows.length > 0) {
                //loop starts from 1. rows[0] points to the header.
                for (i = 1; i < grid.rows.length; i++) {
                    //get the reference of first column
                    if (index > 0) {
                        cell = grid.rows[i].cells[index];
                        for (j = 0; j < cell.childNodes.length; j++) {
                            //if childNode type is CheckBox
                            if (cell.childNodes[j].type == "checkbox") {
                                //assign the status of the Select All checkbox to the cell checkbox within the grid
                                cell.childNodes[j].checked = checkboxId.checked;
                            }
                        }

                    }
                }
            }
        }

//Calling of function

XML

<HeaderTemplate>
                                                                                <asp:CheckBox ID="chkHeader" Text="Check" runat="server" ToolTip="Check All" onclick="return CheckAll(chkHeader,columnNo);" />
                                                                            </HeaderTemplate>

This works for me
try and give replay
Best Luck