getting index for link button in gridview

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i have a gridview and there is two field.

1. document path which is visible false
2. title of document and it is link button.

so, if i have 5 documents title so when i click on particular title it`s path automatically take and open file from some folders like Admin/document/xx.pdf .. Here xx.pdf is title come from selected link button and that file i want to open in same window.

Thankss...
Mitesh

Posted 19-Apr-12 23:31pm

Mits Machhi

Updated 19-Apr-12 23:52pm

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Praveen Meghwal 20-Apr-12 5:38am

Please make your question more clear and if possible post code snippets.

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*Karthik Harve* · Answer 1 · 2012-04-19T23:51:00

Hi,
Set the Command Name for Link Button as "OpenDoc".

I assume that the document path you are saving in ItemTemplate of the gridview as a label with id "lblDocPath".

On GridView Command Event add this below code.

C#

//GridView Command Event
  
   if(e.CommandName=="OpenDoc")
   {
       Label docPath = (Label)((sender as LinkButton).Parent.FindControl("lblDocPath"));
       System.Diagnostics.Process.Start(docPath.Text);
   }

hope it works