Dynamic Menu using XSLT (IF CONDITION)

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Hi,
I have a dynamic menu in my project using XSLT.
I have columns like menuid,menuname,childroot(bit). I want to set navigate url for menu when the childroot is false.

Thanks in Advance.

Thanks,
Subbu

Posted 31-May-12 18:43pm

ThangamSundar

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Andreas Gieriet · Answer 1 · 2012-06-04T05:36:00

Solution 1

Do you know the <xsl:choose...> command.
Try that one.
Cheers
Andi

Posted 4-Jun-12 5:36am

Andreas Gieriet