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See more: XML Color VB.NET DataGridView , +
Dear My Friends of Senior Programmer,

Please Help me, my Problem is cannot retrieve and load the color from my XML file into datagridview (EVENT: FORMTES3_LOAD). the application isn't error but the display of my Datagridview become irregular.

below is my FULL Source Code:

Note : the component is windows form, button, colordialog and datagridview


Imports System
Imports System.IO
Imports System.Xml
 
Public Class FormTes3
 
Dim Doc As XmlDocument = New XmlDocument
 
    Dim rowClicked As Integer
    Dim colorName As String
 
Private Sub CreateNewColorElement(ByVal rowID As Integer) ', ByVal columnIndex As Integer)

        'Create Row Node & ID Attribute
        Dim rowNode As XmlNode = Doc.CreateElement("Row")
        Dim idAttribute As XmlAttribute = Doc.CreateAttribute("rowID")
        idAttribute.Value = rowID.ToString
        rowNode.Attributes.Append(idAttribute)
 
        'Column Node
        Dim columnNode As XmlNode = Doc.CreateElement("Profile")
 
        'BackColor
        Dim backColor As XmlAttribute = Doc.CreateAttribute("BackColor")
        backColor.Value = colorName
        columnNode.Attributes.Append(backColor)
 
        rowNode.AppendChild(columnNode)
        Doc.DocumentElement.AppendChild(rowNode)
 
    End Sub
 

Private Function GetHexColor(ByVal colorObj As System.Drawing.Color) As String
        Return "#" & Hex(colorObj.R) & Hex(colorObj.G) & Hex(colorObj.B)
    End Function
 

    Private Sub DataGridView1_MouseUp(sender As Object, e As System.Windows.Forms.MouseEventArgs) Handles DataGridView1.MouseUp
 
        Dim result As DialogResult
 
        If e.Button = Windows.Forms.MouseButtons.Right Then
 
            rowClicked = DataGridView1.HitTest(e.Location.X, e.Location.Y).RowIndex
 
    result = ColorDialog1.ShowDialog()
 
            If result = DialogResult.OK Then
 
                Dim rowIndex As Integer = rowClicked
 
   DataGridView1.Rows(rowClicked).DefaultCellStyle.BackColor = ColorDialog1.Color   'Running Well

                colorName = GetHexColor(ColorDialog1.Color)
CreateNewColorElement(rowIndex)
 
 ElseIf result = DialogResult.Cancel Then
 
                Return
 
            End If
 
        End If
 
    End Sub
 

 
  Private Sub FormTes3_Load(sender As Object, e As System.EventArgs) Handles Me.Load
 
        ' Populate the grid
        DataGridView1.Columns.Add("Column1", "Column 1")
        DataGridView1.Columns.Add("Column2", "Column 2")
        DataGridView1.Columns.Add("Column3", "Column 3")
 
        DataGridView1.Rows.Add("A", "B", "C")
        DataGridView1.Rows.Add("A", "B", "C")
        DataGridView1.Rows.Add("A", "B", "C")
        DataGridView1.Rows.Add("A", "B", "C")
        DataGridView1.Rows.Add("A", "B", "C")
 
        'In your constructor 
        Doc.AppendChild(Doc.CreateElement("DataGridView"))
 
        If System.IO.File.Exists((Application.StartupPath + "\test.xml")) Then
            Dim row As Integer
            Dim column As Integer
            Dim backColor As String
 
            Doc = New XmlDocument
            Doc.Load((Application.StartupPath + "\test.xml"))
 
            For Each node As XmlNode In Doc.SelectNodes("//Row")
                row = Convert.ToInt32(node.Attributes("rowID").InnerText)
                MsgBox(row)
 
backColor = node.FirstChild.Attributes("BackColor").InnerText
                MsgBox(backColor)
 
                DataGridView1.Rows(row).DefaultCellStyle.BackColor = Color.FromName(backColor)
 

  Next
 
        End If
 
    End Sub
 

 
    Private Sub FormTes3_FormClosing(sender As Object, e As System.Windows.Forms.FormClosingEventArgs) Handles Me.FormClosing
        'Doc.Save((Application.StartupPath + "\DataGrid.xml"))

        Dim saveFile As SaveFileDialog = New SaveFileDialog
        saveFile.InitialDirectory = Application.StartupPath
        saveFile.Filter = "XML files (*.xml)|*.xml"
 
        Dim dr As DialogResult = DialogResult.Yes
 
        If (MessageBox.Show("Do you want to save XML Style?", "Grid Style", MessageBoxButtons.YesNo, MessageBoxIcon.Question) = dr) Then
            If (saveFile.ShowDialog = DialogResult.OK) Then
                Doc.Save(saveFile.FileName)
            End If
 
        End If
 
    End Sub
 

 
End Class


Thank you in advance for any help you can provide, my brothers Big Grin | :-D


Regards,

Agus Salim (Indonesia)

WEB: www.7global.asia

eMail: *******@asia.com
Posted 26-Jul-12 23:37pm
Edited 6-Aug-12 9:24am
v2
Comments
Sergey Alexandrovich Kryukov at 6-Aug-12 15:43pm
   
Not a question; the issue is not explained.
--SA

1 solution

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Solution 1

Your problem seems to be how you read you XML file. You could do something like this:

Dim name as string
 
Public Sub Load(ByVal p_XMLfilename As String)
       XMLFilename = p_XMLfilename
 
       Dim x As New System.Xml.XmlDocument
       x.Load(p_XMLfilename)
 
       Dim x_nodes As System.Xml.XmlNodeList = x.SelectNodes("DataGridView")
       For Each node As System.Xml.XmlNode In x_nodes
 
           For Each node2 As System.Xml.XmlNode In node
               Select Case node2.Name
                   Case Is = "FirstName" : name = node2.InnerText
 
               End Select
           Next
 
       Next
   End Sub

There also seems to be a problem regarding the storage of the values in you xml document.
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