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See more: XML Color VB.NET DataGridView , +
Dear My Friends of Senior Programmer,
Please Help me, my Problem is cannot retrieve and load the color from my XML file into datagridview (EVENT: FORMTES3_LOAD). the application isn't error but the display of my Datagridview become irregular.
below is my FULL Source Code:
Note : the component is windows form, button, colordialog and datagridview

Imports System
Imports System.IO
Imports System.Xml
Public Class FormTes3
Dim Doc As XmlDocument = New XmlDocument
    Dim rowClicked As Integer
    Dim colorName As String
Private Sub CreateNewColorElement(ByVal rowID As Integer) ', ByVal columnIndex As Integer)

        'Create Row Node & ID Attribute
        Dim rowNode As XmlNode = Doc.CreateElement("Row")
        Dim idAttribute As XmlAttribute = Doc.CreateAttribute("rowID")
        idAttribute.Value = rowID.ToString
        'Column Node
        Dim columnNode As XmlNode = Doc.CreateElement("Profile")
        Dim backColor As XmlAttribute = Doc.CreateAttribute("BackColor")
        backColor.Value = colorName
    End Sub

Private Function GetHexColor(ByVal colorObj As System.Drawing.Color) As String
        Return "#" & Hex(colorObj.R) & Hex(colorObj.G) & Hex(colorObj.B)
    End Function

    Private Sub DataGridView1_MouseUp(sender As Object, e As System.Windows.Forms.MouseEventArgs) Handles DataGridView1.MouseUp
        Dim result As DialogResult
        If e.Button = Windows.Forms.MouseButtons.Right Then
            rowClicked = DataGridView1.HitTest(e.Location.X, e.Location.Y).RowIndex
    result = ColorDialog1.ShowDialog()
            If result = DialogResult.OK Then
                Dim rowIndex As Integer = rowClicked
   DataGridView1.Rows(rowClicked).DefaultCellStyle.BackColor = ColorDialog1.Color   'Running Well

                colorName = GetHexColor(ColorDialog1.Color)
 ElseIf result = DialogResult.Cancel Then
            End If
        End If
    End Sub

  Private Sub FormTes3_Load(sender As Object, e As System.EventArgs) Handles Me.Load
        ' Populate the grid
        DataGridView1.Columns.Add("Column1", "Column 1")
        DataGridView1.Columns.Add("Column2", "Column 2")
        DataGridView1.Columns.Add("Column3", "Column 3")
        DataGridView1.Rows.Add("A", "B", "C")
        DataGridView1.Rows.Add("A", "B", "C")
        DataGridView1.Rows.Add("A", "B", "C")
        DataGridView1.Rows.Add("A", "B", "C")
        DataGridView1.Rows.Add("A", "B", "C")
        'In your constructor 
        If System.IO.File.Exists((Application.StartupPath + "\test.xml")) Then
            Dim row As Integer
            Dim column As Integer
            Dim backColor As String
            Doc = New XmlDocument
            Doc.Load((Application.StartupPath + "\test.xml"))
            For Each node As XmlNode In Doc.SelectNodes("//Row")
                row = Convert.ToInt32(node.Attributes("rowID").InnerText)
backColor = node.FirstChild.Attributes("BackColor").InnerText
                DataGridView1.Rows(row).DefaultCellStyle.BackColor = Color.FromName(backColor)

        End If
    End Sub

    Private Sub FormTes3_FormClosing(sender As Object, e As System.Windows.Forms.FormClosingEventArgs) Handles Me.FormClosing
        'Doc.Save((Application.StartupPath + "\DataGrid.xml"))

        Dim saveFile As SaveFileDialog = New SaveFileDialog
        saveFile.InitialDirectory = Application.StartupPath
        saveFile.Filter = "XML files (*.xml)|*.xml"
        Dim dr As DialogResult = DialogResult.Yes
        If (MessageBox.Show("Do you want to save XML Style?", "Grid Style", MessageBoxButtons.YesNo, MessageBoxIcon.Question) = dr) Then
            If (saveFile.ShowDialog = DialogResult.OK) Then
            End If
        End If
    End Sub

End Class


Thank you in advance for any help you can provide, my brothers Big Grin | :-D

Agus Salim (Indonesia)
eMail: *******
Posted 27-Jul-12 0:37am
Edited 6-Aug-12 10:24am
Sergey Alexandrovich Kryukov at 6-Aug-12 15:43pm
Not a question; the issue is not explained.

1 solution

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Solution 1

Your problem seems to be how you read you XML file. You could do something like this:
 Dim name as string
 Public Sub Load(ByVal p_XMLfilename As String)
        XMLFilename = p_XMLfilename
        Dim x As New System.Xml.XmlDocument
        Dim x_nodes As System.Xml.XmlNodeList = x.SelectNodes("DataGridView")
        For Each node As System.Xml.XmlNode In x_nodes 
            For Each node2 As System.Xml.XmlNode In node
                Select Case node2.Name
                    Case Is = "FirstName" : name = node2.InnerText
                End Select
    End Sub
There also seems to be a problem regarding the storage of the values in you xml document.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

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