open/save file dialog box in asp.net

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4.00/5 (1 vote)

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Hi ............

I want to Export grid view data to excel.I have no problem in this but only problem is
that Excel file is storing in Solution itself.I want to show a dialog box for asking user to select path to store that excel file.

here is my code

protected void btnExport_Click(object sender, EventArgs e)
{
DataTable dt = new DataTable();
dt = Session["data"] as DataTable;
string FolderPath;

StreamWriter objSw;
//Create CSV file
if (Directory.Exists(Server.MapPath("~/Reports")))
{
FolderPath = Server.MapPath("~/Reports");

objSw = new StreamWriter(FolderPath + "/TrackRequest" + DateTime.Now.ToString("ddMMMyyyyHHmmss") + ".csv");
}
else
{
FolderPath = Server.MapPath("~/Reports");

Directory.CreateDirectory(FolderPath);

objSw = new StreamWriter(FolderPath + "/TrackRequest" + DateTime.Now.ToString("ddMMMyyyyHHmmss") + ".csv");
}

//get table from GridView1
DataTable objDt = dt; //((DataSet)gvPayDetail.DataSource).Tables[0];

//Get No Of Column in GridView
int NoOfColumn = objDt.Columns.Count;

//Create Header
for (int i = 0; i < NoOfColumn; i++)
{
objSw.Write(objDt.Columns[i]);

//check not last column
if (i < NoOfColumn - 1)
{
objSw.Write(",");
}
}
objSw.Write(objSw.NewLine);

//Create Data
foreach (DataRow dr in objDt.Rows)
{
for (int i = 0; i < NoOfColumn; i++)
{
objSw.Write(dr[i].ToString());

if (i < NoOfColumn - 1)
{
objSw.Write(",");
}
}
objSw.Write(objSw.NewLine);
}
objSw.Close();
}

Posted 27-Nov-12 19:26pm

surajemo

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ManojDhobale · Answer 1 · 2012-11-27T19:53:00

Use datatable to excel function

private void DataTableToCSVFile(string filename, DataTable dt)
   {
       HttpContext context = HttpContext.Current;
       context.Response.Clear();
       DataTable dtExcel = dt;
       foreach (DataColumn column in dtExcel.Columns)
       {
           context.Response.Write(column.ColumnName + ",");
       }
       context.Response.Write(Environment.NewLine);
       foreach (DataRow row in dtExcel.Rows)
       {
           for (int i = 0; i < dtExcel.Columns.Count; i++)
           {
               context.Response.Write(row[i].ToString().Replace(",", string.Empty) + ",");
           }
           context.Response.Write(Environment.NewLine);
       }
       context.Response.ContentType = "text/csv";
       context.Response.AppendHeader("Content-Disposition", "attachment; filename=" + filename + "_" + DateTime.Now + ".csv");
       context.Response.End();
   }

Krunal Rohit · Answer 2 · 2012-11-27T19:28:00

Solution 1

Include this :

C#

using System.Windows.Forms;
OpenFileDialog openFileDialog = new OpenFileDialog();

Posted 27-Nov-12 19:28pm

Krunal Rohit

Comments

Dave Kreskowiak 26-Oct-15 23:25pm

Ummm... WRONG on so many levels it's not funny.

You're seriously going to tell him to put up an OpenFile dialog on a web server where no human will ever see it?? This is a ASP.NET application, not Windows Forms.