How to show an ASP Button only when FileUpload has file chosen

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Hi,

I would like to know how to achieve the following:

Show (hidden with code behind on page load) an ASP Button, when the FileUpload ASP control has a file selected.

aspx

XML

<asp:FileUpload ID="FileUpload1" runat="server" onchange="showButton()"/>
                       <p><asp:Button ID="Button1" runat="server"  Text="Upload File" />&nbsp;</p>

When FileUpload1 has a file selected the onchange should fire
(Button 1 stays hidden and does not show)

Javascript:

XML

<script type ="text/javascript" >
          function showButton() {
              document.getElementById('<%=Button1.ClientID%>').style.visibility = "visible";
          }
</script>

but this does not work.

Please let me know what I am doing wrong.

(should Button1.Visible=true; be used in codebehind instead, if so , how in the aspx file do you tell it to do so?)

Posted 11-Jan-13 19:13pm

AU Jase

Updated 11-Jan-13 19:14pm

v2

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2 solutions

Solution 2

Use

if (FileUpload1.hasfile==true)
{

// Your Statement//////////////
}

Posted 13-Jan-13 20:22pm

kanjolia gopal

Comments

Member 12915803 2-Feb-17 2:07am

i am getting error when i do this step any other solution for this.

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Tharaka MTR · Accepted Answer · 2013-01-11T23:33:00

Try this

ASP.NET

<asp:fileupload id="fileupload1" runat="server" onchange="showButton()" xmlns:asp="#unknown" />
<asp:button id="btnUpload" runat="server" text="Upload" style="display:none" xmlns:asp="#unknown" />

JavaScript

<script type ="text/javascript" >
        function showButton() {
            document.getElementById("<%=btnUpload.ClientID%>").style.display = "";
        }
    </script>