How can I store students scores outside the loop in a 2D jagged array? (

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package quera;

import java.util.Scanner;
public class Quera {

  
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("How many students do you have?");
        int n = scanner.nextInt();

        for (int i = 0 ; i < n ;i++){
        System.out.println("Enter their names and the number of courses in order :");
        String student1 = scanner.next();
        int course = scanner.nextInt();
        System.out.println("Enter her\\his scores : " );
            for(int x =0 ; x < course ; x++){
                  int score = scanner.nextInt();
               long[][] scores = new  long[n][];
               
              
        }
            
       
         }
        
       
    }
    
}

What I have tried:

I need to save the scores in a 2D jagged array and then print them all with the average grades of each student.

Posted 21-Oct-21 12:41pm

MELIKA Kazemi

Updated 22-Oct-21 2:33am

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2 solutions

Solution 2

package quera;

import java.util.Scanner;
public class Quera {

  
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        System.out.println("How many students do you have?");
        int n = scanner.nextInt();

        for (int i = 0 ; i < n ;i++){
        System.out.println("Enter their names and the number of courses in order :");
        String student1 = scanner.next();
       
        int course = scanner.nextInt();
        
        System.out.println("Enter her\\his scores : " );
        long[][] scores = new  long[n][];
               scores[i] = new long[course];
            for(int x =0 ; x < course ; x++){
             
               
              

              
        }
         
       
         }
        
       
    }
    
}

Posted 22-Oct-21 2:33am

MELIKA Kazemi

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Richard MacCutchan · Accepted Answer · 2021-10-21T21:55:00

Solution 1

You need to allocate each sub-array as you process each student's data.

Java

long[][] scores = new  long[n][];
score[i] = new long[course];
//
// you now add each course score in order to the score[i] array.
// you probably also need to keep a note of the course count in the array,
// so you do not try and access non-existent elements later.

Posted 21-Oct-21 21:55pm

Richard MacCutchan

Comments

MELIKA Kazemi 22-Oct-21 8:39am

Thank you so much.It was really helpful.
In the end I need to print all the scores with their average Should I use this array?
How can I pull out scores out of the loop?

Richard MacCutchan 22-Oct-21 8:56am

Think about what you are trying to do, one step at a time. For each sub-array you need to remember how many scores are inside it. So instead of new long[course]; use new long[course + 1];. You can then put the count of courses in element[0], and the actual scores in the remainder. You can also use that value later on, as a loop counter, when you need to print the scores. So something like:

score[i] = new long[course + 1];
score[i][0] = course; // save the count of courses
for (int j = 1; j <= course; j++) {
    // get the score for the next course
    // save it in the next element
    score[i][j] = // the score for this course
}

You may also need separate array for the student names.