How do I print all possible digits that can be formed with these n digits?

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i need to get all possible digits that can be formed with these n digits. But I am getting a wrong output.
For example,

Input:
123

Output:
1 2 3 11 22 33 12 23 32 31 21 111 222 333 121 131 133......

But my code is giving output such that it prints only digits of length of input.

What I have tried:

mycode

from itertools import permutations

seq = permutations(['a','b','c'])

for p in list(seq):
   print(p)

Posted 30-Jan-22 16:45pm

sanjay surya

Updated 30-Jan-22 21:10pm

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Comments

Graeme_Grant 30-Jan-22 22:53pm

This sounds like a courseware homework question. This link should help: Google Search[^]

2 solutions

Solution 1

While we are more than willing to help those that are stuck, that doesn't mean that we are here to do it all for you! We can't do all the work, you are either getting paid for this, or it's part of your grades and it wouldn't be at all fair for us to do it all for you.

So we need you to do the work, and we will help you when you get stuck. That doesn't mean we will give you a step by step solution you can hand in!
Start by explaining where you are at the moment, and what the next step in the process is. Then tell us what you have tried to get that next step working, and what happened when you did.

If you are having problems getting started at all, then this may help: How to Write Code to Solve a Problem, A Beginner's Guide[^]
I'd think about converting the input into separate values first - a List perhaps - and then think back to when you were taught about Permutations and Combinations.

Posted 30-Jan-22 20:03pm

OriginalGriff

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CPallini · Accepted Answer · 2022-01-30T21:10:00

Solution 2

You have to use the cartesian product.
Try

from itertools import product
l = ['a', 'b', 'c']
for k in range(1,len(l)+1):
  for cp in product(l, repeat = k):
    print(cp)

Posted 30-Jan-22 21:10pm

CPallini