How do I print more than 3 specific element in a list using for loop

Question

1.00/5 (1 vote)

See more:

song = ['always', 'look', 'on', 'the','bright','side','of', 'life']

how should I write a for loop, that it may print

always
look
side
of
life

What I have tried:

I tried break and continue functions. tried randint using numpy

Posted 11-Aug-22 20:04pm

johng92

Updated 12-Aug-22 1:44am

Add a Solution

Comments

Sauradipta Chaudhury 12-Aug-22 2:23am

Can you share the code that you tried?

johng92 12-Aug-22 2:46am

I found this one:

skipcount = -1
song = ['always', 'look', 'on', 'the','bright','side','of', 'life']
for sing in song: 
    if sing == 'look' and skipcount <= 0: 
        print (sing) 
        skipcount = 3 
    elif skipcount > 0: 
        skipcount = skipcount - 1
        continue 
    elif skipcount == 0:
        print ('a' + sing)
        skipcount = skipcount - 1
    else: 
        print (sing)

this one I found in the internet , But I am not able to understand. from which side it is skip counting , from which side.

Patrice T 12-Aug-22 2:35am

Show your code for help.
What is the rule to know what to print ?

3 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Patrice T · Answer 1 · 2022-08-12T01:44:00

Solution 3

Quote:
this one I found in the internet , But I am not able to understand. from which side it is skip counting , from which side.

Get rid of this code, it is specially crafted for this specific input and specific skip.

My approach would be :

Python

song = ['always', 'look', 'on', 'the','bright','side','of', 'life']
# list of positions to keep
keep = [0, 1, 4, 5, 6, 7]
for pos in keep:
    print (song[pos])

Posted 12-Aug-22 1:44am

Patrice T

Updated 12-Aug-22 1:45am

v2

Comments

sunnyjohn 18-Oct-22 13:06pm

Thanks a lot Patrice:) It solved my query.
Python is meant to make things easier, I was making it difficult.

Patrice T 18-Oct-22 13:35pm

You should accept useful solutions.
It reward authors and close the question as solved.

sunnyjohn 18-Oct-22 13:48pm

Okay, I will. thanks for precious suggestions.

OriginalGriff · Answer 2 · 2022-08-11T20:22:00

The simplest solution is to have a separate collection of "insignificant words":

Python

ignoreThese = ['on', 'the']

And in your loop just check if the current word is included in the "ignorable" collection.
If it is, don't print it. Otherwise, do.

That way, it's more flexible - it can cope with any input string without "special case" coding being required.

Give it a try - Python has the in operator which would help - you'll see what I mean!

Sauradipta Chaudhury · Answer 3 · 2022-08-12T01:04:00

skipcount = 1
song = ['always', 'look', 'on', 'the','bright','side','of', 'life']
for sing in song: 
    if skipcount != 3 and skipcount != 4: 
        print (sing) 
        skipcount = skipcount + 1
    else: 
        continue

The above logic will work when you have

['always', 'look', 'on', 'the','bright','side','of', 'life']

as your fixed input and you only want to skip the

3rd & 4th

words.

But, if you want to skip a specific set of words that you need to skip from any given array of words then you should follow what @OriginalGriff mentioned.

How do I print more than 3 specific element in a list using for loop

3 solutions

Solution 3

Solution 1

Solution 2

Add your solution here

Preview 0