How do I use the math.sqrt method in a switch statement?

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I'm creating a scientific calculator app and currently am unable to make the square root button work. I'm using a switch statement to handle the calculator symbols and not sure exactly how to make this work.

What I have tried:

function handleSymbol(symbol) {
  switch (symbol) {
    case "C":
      buffer = "0";
      runningTotal = 0;
      break;

    case "=":
      if (previousOperator === null) {
        return;
      }
      removeOperation(parseInt(buffer));
      previousOperator = null;
      buffer = runningTotal;
      runningTotal = 0;
      break;

    case "⬅":
      if (buffer.length === 1) {
        buffer = "0";
      } else {
        buffer = buffer.substring(0, buffer.length - 1);
      }
      break;
    case "√":
let sqrt() = Math.sqrt(value);
      break;

    case "+":
    case "-":
    case "*":
    case "/":
    case "%":
      handleMath(symbol);
      break;
  }
}

Posted 17-Aug-22 0:34am

Emma747

Updated 17-Aug-22 0:53am

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OriginalGriff · Answer 1 · 2022-08-17T00:53:00

Look at your handleMath method - we can't see it - and look at where it gets it's values from, and what it does with results: You want to do a very similar thing but with just the next value.

But this code is never

let sqrt() = Math.sqrt(value);

going to work: sqrt isn't a method, and let variables go out of scope very quickly and the result would be discarded anyway even if you corrected that: JavaScript Let[^]

To be honest, it looks like you found most of the code you need on the internet and are trying to modify it by guesswork and hope, without any understanding of what the code actually does or how it does it. That isn't going to work: I'd strongly suggest that you try to write your own code rather than try to cheat with someone elses!