Adding array elements through recursion

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I do not understand the output.why isn't picking the correct array element?

What I have tried:

import array as arr
def sum_array(ar,n,i):
    print(i)
    print(ar[i])
    if(i>= n-1):
        return 0
    else:
        return ar[i] + sum_array(ar , n , i+1)
        
a = arr.array('i',{5,3,5,8})
n = len(a)
num = sum_array(a , n , 0)
print(num)

Posted 16-Sep-22 8:31am

Nitraj

Updated 16-Sep-22 8:56am

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Richard MacCutchan 17-Sep-22 4:55am

You can create an array just as easily with:

a = [ 5, 3, 5, 8 ]

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k5054 · Accepted Answer · 2022-09-16T08:56:00

When you declare your array a you are using curly brackets {} rather than square brackets []. The curly brackets is used to define a set, so first python creates a set from {5, 3, 5, 8 } which gives the set { 3, 5, 8 } which is then assigned as the contents of the array object. That means that when you take len(a) you get the value 3, rather than 4, which is what you expected.