How to convert list<object> into dictionary<string, string>

Question

1.00/5 (1 vote)

See more:

i have a model class

public class studentData
{
    public string ID{ get; set; }
    public string Name{ get; set; }

}

i create a List and assign the values to this model
sample code:-

  List<studentData> std=new <studentData>{
new student{ID="1",Name="teststudent1"},
new student{ID="2",Name="teststudent2"},
}

now i need to convert this list into "dictionary <string,string>"

i need my list into dictionary look like :-

"studentdata": [
{
"ID": "1",
"Name": "teststudent1"
},
{
"ID": "2",
"Name": "teststudent2"
}
]

can any one suggest me the solution.

What I have tried:

i tried this but it's only working when in my list value are exsits only for index[0] if value are in more then 1 index in the list then it's not working.

var item = JsonConvert.SerializeObject(StudentList);
item = item.Replace("[", "").Replace("]","");
var vendordata = JsonConvert.DeserializeObject<dictionary<string, dynamic>>(item);

Posted 19-Sep-22 0:20am

TCS54321

Updated 19-Sep-22 22:08pm

v6

Add a Solution

Comments

Richard MacCutchan 19-Sep-22 6:27am

Does List<T> have a ToDictionary method? And what problem are you trying to solve?

TCS54321 19-Sep-22 6:37am

i want to convert my List into Dictionary. check my question. i updated my question

Richard MacCutchan 19-Sep-22 6:43am

Yes but you ignored both of my questions.

TCS54321 19-Sep-22 6:49am

i did net get my list data into Dictionary. i used this code to convert list into dictionary
----->>> Dictionary<studentdata, studentdata=""> dict = mylist.ToDictionary(x=>x);

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

OriginalGriff · Answer 1 · 2022-09-19T01:16:00

Solution 1

A Dictionary has two parts: a Key and a Value.
You code sets the Key only, so the Value is assumed to be the whole of the class instance that the initial collection had: a Dictionary<string, studentData>> rather than a

Dictionary<string, string>

.

To get a string Value you have to explicitly tell the ToDictionary method what value to use:

C#

private void MyButton_Click(object sender, EventArgs e)
    {
    List<studentData> std = new List<studentData>{
        new studentData { ID = "1", Name = "teststudent1" },
        new studentData { ID = "2", Name = "teststudent2" },
        };
    Dictionary<string, string> dict = std.ToDictionary(k => k.ID, v => v.Name);
    }

Posted 19-Sep-22 1:16am

OriginalGriff

Updated 19-Sep-22 2:26am

v2

Comments

TCS54321 20-Sep-22 4:00am

thanx for you reply but your solution does not work in my case. i need the output look like this --->

"studentdata": [
{
"ID": "1",
"Name": "teststudent1"
},
{
"ID": "2",
"Name": "teststudent2"
}
]

TCS54321 20-Sep-22 4:04am

(ID, Name) should be a Key and (1,teststudent1/2,teststudent2) should be a value

OriginalGriff 20-Sep-22 4:24am

Then change it to do so: but remember that if your key is a class, then unless you create a class and implement comparison operators the reference comparison will be used, not the class property values. Since you will be creating new instances for each row, the references will be different for each even if the ID and Name are identical!

I think you need to think about why you are doing this - it sounds a lot like an over-thought solution from over here!