Quote:
When i run it and try the year 1918, it gives me two outputs,one for the if year condition and the other for if leap condition, any ways to fix it?
this is exactly what this program is done for.
Just a guess about what you want, this should be closer :
leap=False
year=int(input("Enter the year:"))
if year==1918:
print('27.09.1918')
else:
if year<1918:
leap=True if (year%4==0) else False
elif year>1918:
leap=True if (year%400==0 or (year%4==0 and year%100!=0)) else False
if leap==True:
print('12.09.{}'.format(year))
break
elif leap==False:
print('13.09.{}'.format(year))
But there is other errors.
Your code do not behave the way you expect, or you don't understand why !
There is an almost universal solution: Run your code on debugger step by step, inspect variables.
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't know what your code is supposed to do, it don't find bugs, it just help you to by showing you what is going on. When the code don't do what is expected, you are close to a bug.
To see what your code is doing: Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.
Debugger - Wikipedia, the free encyclopedia[
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Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[
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Basic Debugging with Visual Studio 2010 - YouTube[
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27.3. pdb — The Python Debugger — Python 3.6.1 documentation[
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Debugging in Python | Python Conquers The Universe[
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pdb – Interactive Debugger - Python Module of the Week[
^]
The debugger is here to only show you what your code is doing and your task is to compare with what it should do.