What is the evaluation of overloaded operators in an expression?

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Like let's say -

A a1,a2,a3,a4;

a1=a2*a3+a1++/2;

Assuming there is a class A and *,+,post increment operator(++) and / are overloaded in class A. a1,a2,a3,a4 are objects of A class.

So what's the order of evaluation of operators in above expression -

If we'll check according to the precedence of operators then * will be evaluated first then / then + and last post increment(++). But I have overloaded multiple operators but they are not working according to the precedence.

Please tell.

What I have tried:

Tried googling and also did experiment but still didn't understand.

Posted 29-Oct-22 6:01am

Utkarsh Singh Rajawat

Updated 29-Oct-22 14:02pm

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OriginalGriff · Answer 1 · 2022-10-29T06:11:00

Solution 1

That's tricky ... Why Does x = ++x + x++ Give Me the Wrong Answer?[^]

Posted 29-Oct-22 6:11am

OriginalGriff

Richard MacCutchan · Answer 2 · 2022-10-29T06:55:00

Solution 2

See also C++ Operator Precedence - cppreference.com[^].

Posted 29-Oct-22 6:55am

Richard MacCutchan

Greg Utas · Answer 3 · 2022-10-29T14:02:00

Whether they've been overloaded or not, the compiler generates code to execute operators in the same order.

If you read the page that Richard linked, I think you'll discover that you're mistaken about the order in which the evaluation occurs for this expression. In any case, I would never write that kind of expression without including parentheses to make the evaluation order clear. There is no prize for eliminating a few keystrokes, notwithstanding some of the "clever" code that you will occasionally see.