Javascript validation not to allow numbers like 12121212 or 3434343434

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<HTML>
 <HEAD>
  <TITLE> </TITLE>

 <script type="text/javascript">
  function formValidation(){
  if (validateAllSame()){
  }
  return false;
  }
  function validateAllSame(){

  var y=document.form1.number.value;
  var x = y.substr(0,2);
  for(int i=0;i<=y.length;i+=2){
  if(y[i] == x){

  }
  return false;
   alert("wrong number");
  }

  return true;
  }

  </script>

 </HEAD>

 <BODY>
  <form name ="form1" action="" onsubmit="return formValidation()">
  Number:<input type="text" name="number" value="">
  <input type="submit" value="Done">
   </form>

 </BODY>
</HTML>

Hi can anyone suggest me what to do with my code..I have tried to write a code that does not allow numbers like 12121212/3434343 etc... Please help me out with the code I am still learning

Posted 10-Mar-13 7:46am

Member 9882454

Updated 10-Mar-13 7:52am

v3

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Member 9882454 10-Mar-13 14:02pm

for(int i=2;i<=y.length;i+=2){
if(y.substr([i],2) != x){
return true;
}

}

return false;
alert("wrong number");
}

I just tried replacing this in my for loop..But it still doesnot seem to work..can anyone check please

2 solutions

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Prasad Khandekar · Answer 1 · 2013-03-10T08:22:00

Solution 1

Hello,

Try following regular expression.

C#

([a-zA-Z0-9]+?)\1+

regards,

Posted 10-Mar-13 8:22am

Prasad Khandekar

Comments

codegirl24 10-Mar-13 14:54pm

Hi Prasad,I have the same problem with the code aswell..
Does the regular expression work for numbers and numbers must not be of format 12121212/5656565

Prasad Khandekar 10-Mar-13 15:16pm

Hi,
It will work with numbers and characters as well. You can use Expresso 3.0 a regular expression tester found here (http://www.ultrapico.com/Expresso.htm) to test various expressions.

codegirl24 10-Mar-13 15:33pm

thanks a lot prasad :) its working

codegirl24 15-Apr-13 4:23am

Prasad Khandekar :Hi,
I have used the above regex for same problem i was facing..But the problem is its not allowing numbers like 78890923454 also...meaning 22,88,99 like numbers also are showing error...But phone numbers can have such numbers in sequence right? Ex:98825609978 etc..
Waiting for your reply...Please guide on this.

Prasad Khandekar 15-Apr-13 6:56am

Hello,

The way you will be checking whether there is a full match could be done as follows

ret = valuetocheck.match(/([a-zA-Z0-9]+?)\1+/gi);
if (ret != null && ret[0] === valuetocheck) alert("ERROR");

For the values you mentioned the first match will be same as the value your checking.

codegirl24 15-Apr-13 13:16pm

Prasad: What is /gi here?
And the problem I am facing is : generally if i enter a phone number like 9880228876,it must not show any error meaning the phone number is acceptable.
But with the above regex it gives an error for above phone number too as invalid number.
Can you please tell me how and where should i improvise?

Prasad Khandekar 15-Apr-13 15:41pm

Hello,

Look at my earlier reply. It shows the possible change required in validateAllSame function. The gi stands for global case-insensitive.

Maciej Los · Answer 2 · 2013-03-10T10:10:00

Solution 2

Have a look here: Trying not to allow numbers like 12121212/34343434 using javascript[^]

Posted 10-Mar-13 10:10am

Maciej Los