Code for performing z-transform on sequence of real numbers

Question

0.00/5 (No votes)

See more:

I have a sequence of real numbers.
I want to perform z-transform on this sequence.
Can anybody help to perform z-transform on sequence of 256 integer values??

Posted 22-Mar-13 23:37pm

Ishpreet Kaur

Add a Solution

2 solutions

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

Sergey Alexandrovich Kryukov · Answer 1 · 2013-03-25T10:08:00

From your question, it's not clear what kind of help you may need.

I would advise you to start here: http://en.wikipedia.org/wiki/Z-transform[^].

If you follow at the further links from this article, you can find some implementations. Or implement the algorithm from scratch, which should not be too hard. If you face problems, we would gladly try to help you.

—SA

Richard MacCutchan · Answer 2 · 2013-03-23T00:15:00

Solution 1

See here[^].

Posted 23-Mar-13 0:15am

Richard MacCutchan

Comments

H.Brydon 25-Mar-13 18:04pm

This link looks for JSON - not what OP was asking about...

Richard MacCutchan 26-Mar-13 5:23am

No, it's a Google search for Z-transform. The json reference in the link is added by Chrome, for reasons known only to the Google developers.

H.Brydon 26-Mar-13 10:38am

Here is what it looks like on my machine:

http://postimg.org/image/inh5ssjo9/

It is a google search for "json".

Richard MacCutchan 26-Mar-13 12:42pm

Well it would appear that Firefox cannot handle that search string correctly. When I click on the link I get a list of links pertaining to Z-transform.