Incorrect syntax near '('.

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query as follows;

SQL

declare #TempTable(SNo int, Stud_ID varchar(10), Stud_Name varchar(100),
      Rcptno varchar(20),Rcptdt varchar(20), RcptAmt varchar(20),Chqtype varchar(20))

But when i run the above query, error shows as follows;

Incorrect syntax near '('.

i think my query is correct but when i run error shows.

what is the problem in my above code.

Please help me.

Regards,
Narasiman P.

Posted 17-Apr-13 17:34pm

Member 8054539

Updated 17-Apr-13 19:38pm

AmitGajjar

v2

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Abhinav S · Answer 1 · 2013-04-17T18:26:00

Solution 2

Using TABLE after declare #TempTable should also work

SQL

declare #TempTable Table(SNo int, Stud_ID varchar(10), Stud_Name varchar(100),
Rcptno varchar(20),Rcptdt varchar(20), RcptAmt varchar(20),Chqtype varchar(20))

Posted 17-Apr-13 18:26pm

Abhinav S

Comments

Aarti Meswania 18-Apr-13 0:48am

5+! :)

Abhinav S 18-Apr-13 2:29am

Thank you.

Aarti Meswania 18-Apr-13 2:30am

Welcome! :)

Rockstar_ · Answer 2 · 2013-04-17T18:02:00

hi,

Use something like this, For creating temporary table...

SQL

create table #temUsers            
(            
MyContactUserID uniqueidentifier,            
MyContactName varchar(200),            
HisContactUserID uniqueidentifier,            
HisContactName varchar(200),            
ConnectionDate datetime          
)

TrushnaK · Answer 3 · 2013-04-17T20:09:00

Solution 3

hi,

use

SQL

create Table #tempTable(SNo int, Stud_ID varchar(10), Stud_Name varchar(100),
    Rcptno varchar(20),Rcptdt varchar(20), RcptAmt varchar(20),Chqtype varchar(20))

Posted 17-Apr-13 20:09pm

TrushnaK

OPees · Answer 4 · 2013-04-17T20:25:00

SQL

-- if want to create Temp table then
create table  ##TempTable
(SNo int, Stud_ID varchar(10), Stud_Name varchar(100),
        Rcptno varchar(20),Rcptdt varchar(20), RcptAmt varchar(20),Chqtype varchar(20))

--if you want to use Table Varriable

declare @TempTable Table(SNo int, Stud_ID varchar(10), Stud_Name varchar(100),
Rcptno varchar(20),Rcptdt varchar(20), RcptAmt varchar(20),Chqtype varchar(20))

Incorrect syntax near '('.

4 solutions

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