php jquery datepicker not working inside forloop

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Hi,

I have a for loop writing out a list of records to a web page, now what I want is to display a link that displays a date, when clicking the link it brings up a dialog box for the user to edit the date, I got that rite but some how when a second record is added it doesnt seem to work,

Thanks

Posted 23-Apr-13 20:55pm

nathan666

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Zoltán Zörgő 24-Apr-13 2:59am

How exactly do you apply with jquery the datepicker on the elements?

nathan666 24-Apr-13 3:01am

Below is the jquery initialized

$(function() {
$("#timeOff").datepicker({ dateFormat: "dd/mm/yy", yearRange: 'c:c+10', changeMonth: true, changeYear: true});
$('#timeOff2').each(function(){
$(this).datepicker({ dateFormat: "dd/mm/yy", yearRange: 'c:c+10', changeMonth: true, changeYear: true});
});

and this is where the datepicker instance is created

<input id="timeOff2" class="datepicker"/></input>
}

nathan666 24-Apr-13 3:39am

so it would be

"<input type="text" name="timeOff" class="DatePicker-needed">|"

and as the loop runs it creats multiple instances of name="timeOff" with class="DatePicker-needed"?

Zoltán Zörgő 24-Apr-13 4:05am

More or less. Look here: http://www.johnrockefeller.net/html-input-forms-sending-in-an-array-in-php/
Names should be unique in a form, but you can use arrays: <input type="text" name="timeOff[]" class="DatePicker-needed">

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**Zoltán Zörgő** · Accepted Answer · 2013-04-23T21:12:00

You wrote, your are using a loop, but you apply the feature based on ID ('#timeOff2'). But there can be only one element on the page with such ID. I am not wondering that it does not work, you mishandle the html standard. Don't reuse ID within page. In this case you should use class. And you don't need each either.

JavaScript

$('.DatePicker-needed').datepicker({ dateFormat: "dd/mm/yy", yearRange: 'c:c+10', changeMonth: true, changeYear: true});