semicolon is put right after if condition plz explain me this code

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this is C Language code where the semicolon is put right after if condition plz explain me this code.

C#

#include<stdio.h>
int main()
{
    int x = 10, y = 100%90, i;
    for(i=1; i<10; i++)
    if(x != y);
        printf("x = %d y = %d\n", x, y);
    return 0;
}

Posted 8-May-13 23:03pm

Tarun Jaiswal

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SoMad 9-May-13 5:09am

I am pretty sure it is simply a b...wait a second, is this homework?

Soren Madsen

Mohibur Rashid 9-May-13 5:20am

virtual +5

SoMad 9-May-13 5:26am

:) thanks.

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CPallini · Answer 1 · 2013-05-08T23:09:00

Solution 1

Such code, albeit valid, make no sense.
It checks ten times if x is different from y and if the condition is satisfied (actually it is NOT satisfied) does NOTHING (due to the semicolon after the if statement: such a semicolon is the 'empty statement').

Posted 8-May-13 23:09pm

CPallini