How to make silder in jquery

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<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
    <title></title>
     <script src="http://code.jquery.com/jquery-1.9.1.js"></script>
  <script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script>
    <script language="javascript" type="text/javascript">
        var _index = 1;
        var myVar;
        var _time = 2000;
        $(document).ready(function () {
            myFunction();
        });

        function Silder() {
            var myarray = ['1.jpg', '2.jpg', '3.jpg', '4.jpg'];
            if (_index > myarray.length) {
                _index = 1;
            }
            $('#mainsilde').fadeOut('slow');
            $("#mainsilde").attr("src", "gal/" + _index + ".jpg");
            $('#mainsilde').fadeIn('slow');
            _index = _index + 1;
           myVar = setTimeout(Silder, _time);

        }
        function SetOnCall(_index) {

          //  $('#mainsilde').fadeOut('slow');
            $("#mainsilde").attr("src", "gal/" + _index + ".jpg");
         //   $('#mainsilde').fadeIn('slow');
        }

        function myFunction() {
            myVar = setTimeout(Silder, _time);
        }

        function myStopFunction(_index) {
            clearTimeout(myVar);
            SetOnCall(_index);
        }
    </script>
    </head>
<body>
<table>
    <tr>
        <td valign="top">
            <div >
                <img src="gal/1.jpg" class="dup" width="100px"  onmouseover="myStopFunction(1);" onmouseout="myFunction();" />
            </div>
            <div class="dup">
                <img src="gal/2.jpg" class="dup" width="100px" onmouseover="myStopFunction(2);" onmouseout="myFunction();" />
            </div>
            <div >
                <img src="gal/3.jpg"  class="dup" width="100px" onmouseover="myStopFunction(3);" onmouseout="myFunction();"/>
            </div >
            <div >
                <img src="gal/4.jpg" class="dup" width="100px" onmouseover="myStopFunction(4);" onmouseout="myFunction();" />
            </div>
        </td>

        <td valign="top">
            <img src="gal/0.jpg" id="mainsilde" width="430px" height="340px"  onmouseover="wait(0);" onmouseout="wait(1);"/>
        </td>

           <td valign="top">
            <div >
                <img src="gal/1.jpg" class="dup" width="100px" onmouseover="myStopFunction(1);" onmouseout="myFunction();" />
            </div>
            <div class="dup">
                <img src="gal/2.jpg" class="dup" width="100px" onmouseover="myStopFunction(2);" onmouseout="myFunction();" />
            </div>
            <div >
                <img src="gal/3.jpg"  class="dup" width="100px" onmouseover="myStopFunction(3);" onmouseout="myFunction();"/>
            </div >
            <div >
                <img src="gal/4.jpg" class="dup" width="100px" onmouseover="myStopFunction(4);" onmouseout="myFunction();" />
            </div>
        </td>
    </tr>
</table>
</body>
</html>

Posted 16-Jun-13 23:52pm

Ravinder Singh Choudhary

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Prasad_Kulkarni · Answer 1 · 2013-06-16T23:58:00

Solution 1

Refer:
Image Slideshow Using jQuery[^]
JQueryui[^]
Simple jquery image slideshow example[^]

Or else explain what exactly the problem you're getting with code snippets in your question.

Posted 16-Jun-13 23:58pm

Prasad_Kulkarni