An entry with the same key already exists.

Question

1.00/5 (3 votes)

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I am getting the below error while running the application ...

In this page I am adding rows dynamically to a table and the rows containing dropdown list,text boxes and required field validator with different ID for each control.

C#

Server Error in '/' Application.
--------------------------------------------------------------------------------

An entry with the same key already exists. 
Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. 

Exception Details: System.ArgumentException: An entry with the same key already exists.

Source Error: 

An unhandled exception was generated during the execution of the current web request. Information regarding the origin and location of the exception can be identified using the exception stack trace below.  

Stack Trace: 


[ArgumentException: An entry with the same key already exists.]
   System.Collections.Specialized.ListDictionary.Add(Object key, Object value) +6241213
   System.Web.UI.ClientScriptManager.RegisterExpandoAttribute(String controlId, String attributeName, String attributeValue, Boolean encode) +272
   System.Web.UI.ScriptRegistrationManager.RegisterExpandoAttribute(Control control, String controlId, String attributeName, String attributeValue, Boolean encode) +115
   System.Web.UI.ScriptManager.RegisterExpandoAttribute(Control control, String controlId, String attributeName, String attributeValue, Boolean encode) +44

[TargetInvocationException: Exception has been thrown by the target of an invocation.]
   System.RuntimeMethodHandle._InvokeMethodFast(IRuntimeMethodInfo method, Object target, Object[] arguments, SignatureStruct& sig, MethodAttributes methodAttributes, RuntimeType typeOwner) +0
   System.RuntimeMethodHandle.InvokeMethodFast(IRuntimeMethodInfo method, Object target, Object[] arguments, Signature sig, MethodAttributes methodAttributes, RuntimeType typeOwner) +72
   System.Reflection.RuntimeMethodInfo.Invoke(Object obj, BindingFlags invokeAttr, Binder binder, Object[] parameters, CultureInfo culture, Boolean skipVisibilityChecks) +251
   System.Reflection.RuntimeMethodInfo.Invoke(Object obj, BindingFlags invokeAttr, Binder binder, Object[] parameters, CultureInfo culture) +28
   System.RuntimeType.InvokeMember(String name, BindingFlags bindingFlags, Binder binder, Object target, Object[] providedArgs, ParameterModifier[] modifiers, CultureInfo culture, String[] namedParams) +2377
   System.Web.UI.WebControls.ValidatorCompatibilityHelper.RegisterExpandoAttribute(Control control, String controlId, String attributeName, String attributeValue, Boolean encode) +170
   System.Web.UI.WebControls.BaseValidator.AddAttributesToRender(HtmlTextWriter writer) +330
   System.Web.UI.WebControls.RequiredFieldValidator.AddAttributesToRender(HtmlTextWriter writer) +18
   System.Web.UI.WebControls.WebControl.RenderBeginTag(HtmlTextWriter writer) +20
   System.Web.UI.WebControls.BaseValidator.Render(HtmlTextWriter writer) +445
   System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27
   System.Web.UI.Control.RenderControl(HtmlTextWriter writer, ControlAdapter adapter) +100
   System.Web.UI.Control.RenderControl(HtmlTextWriter writer) +25
   System.Web.UI.Control.RenderChildrenInternal(HtmlTextWriter writer, ICollection children) +208
   System.Web.UI.Control.RenderChildren(HtmlTextWriter writer) +8
   System.Web.UI.WebControls.TableCell.RenderContents(HtmlTextWriter writer) +57
   System.Web.UI.WebControls.WebControl.Render(HtmlTextWriter writer) +32
   System.Web.UI.Control.RenderControlInternal(HtmlTextWriter writer, ControlAdapter adapter) +27

Posted 13-Aug-13 3:31am

prasy123

Updated 13-Aug-13 5:17am

v3

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Comments

TrushnaK 13-Aug-13 9:40am

where you get this error?

prasy123 13-Aug-13 9:46am

After the submit button click event the page showing this error.

OriginalGriff 13-Aug-13 9:55am

No, we would need to see the code fragment generating the error...

prasy123 13-Aug-13 10:03am

Dim tr As New TableRow()
Dim td1 As New TableCell()

Dim rfvCANnew As New RequiredFieldValidator
rfvCANnew.ID = "rfvCANnew" + i
rfvCANnew.ErrorMessage = "CAN Field is Required"
rfvCANnew.ValidationGroup = "grpSave"
rfvCANnew.ControlToValidate = drpCan.ID
rfvCANnew.InitialValue = 0
rfvCANnew.Display = ValidatorDisplay.None
rfvCANnew.SetFocusOnError = True

td1.Controls.Add(rfvCANnew)
tr.Cells.Add(td1)
tblNewCan.Rows.Add(tr)

// Also given increment for i in each row generation..

And I am using this table in the body of a mail by using the below code
Dim SBEoc As New StringBuilder()
Dim SWEoc As New StringWriter(SBEoc)
Dim htmlTWEoc As New HtmlTextWriter(SWEoc)
tblNewCan.RenderControl(htmlTWEoc)
sendEMailDraft(TableHTMLEoc)

prasy123 13-Aug-13 10:05am

After adding this field validator making this exception otherwise that code was working fine

Sergey Alexandrovich Kryukov 13-Aug-13 10:10am

The exception information is 100% clear. The data with some key is added to a dictionary for the key which was already added before. Under debugger, find out which key is that and why it is added again. It could be empty string, or something like that.
—SA

ak99372 16-Jul-14 17:45pm

The information is 100% clear but provides 0% value to programmer. The error should state which control and which which value are duplicate. Then it would actually say something useful.

Sergey Alexandrovich Kryukov 16-Jul-14 19:49pm

Not true. Not true at all. It depends on who is calling oneself "programmer"... :-)
This requirement to such an exception is totally unreasonable. A programmer would figure out the rest using the debugger.
—SA

ak99372 4-Aug-14 20:28pm

It is unreasonable for programmer to use debugger for something that should have been easily explained by the exception error message ... you must be one of those programmers that (ab)use debugger to "code" instead of actually understanding what you code.

Sergey Alexandrovich Kryukov 5-Aug-14 0:22am

Please don't tell about people something you have no idea about. It may help you avoiding some funny situations.

Yes, you are right, it would be unreasonable to debug something when you already understand the nature of the problem, say, from the exception. But the trouble is, OP did not show the signs of such understanding. I cannot see your logic. First, you say that exception information provides zero value (and put some potentially unreasonable requirement to the exception, not explaining how this requirement should be met and what to do if in some code you are using it is not met), and when I say that the debugging can complement this information, you say that exception should be enough, the point I started with.

—SA

Sergey Alexandrovich Kryukov 16-Jul-14 19:54pm

By the way, would you stop posting your fake "solutions". You are just answering to yourself, and not giving anyone anything useful. This is abusive behavior. Who is interested to know that you did some mistake and then fixed it? If you have something to help people with, write at least a short Tips & Tricks article.

Please consider this just as a good advice. Such posts will only give you down-voted and abuse reports.

—SA

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prasy123 · Answer 1 · 2013-08-13T05:21:00

Solution 1

Before rendering the table control the Validator controls need to remove or need to set "visible=false"

Please refere: http://forums.asp.net/t/1632629.aspx/1[^] site.

Posted 13-Aug-13 5:21am

prasy123