Little Question About C Style Array In Struct.?

If you want to use the form

get (char* s, streamsize n)

the get function tries to read n-1 characters from the stream and then appends a null-terminator. If you use n==1 then nothing can be read. If you want to use n==2 then you must provide space for the null-terminator, which you would do by:

char name[5][2];

Alternatively you could use the get function that reads a single character:

cin.get(dummy.name[i][1]);

In that case your out function would not work, because it also is written in a way so that it expects null-terminated strings. Instead of

cout << dummy.name[j] << " || ";

you need to do

cout << dummy.name[j][1] << " || ";

The reason is that dummy.name[j] specifies an object of type char[] (or char*) in which case the << operator expects a null-terminated c-string. dummy.name[j][1] however is a single character and the << operator knows how to deal with that and does not expect a null-terminator behind it.

Hope that helps.

Presuming C# here, so ... in your Input Window, an edit control, have you tried using an 'input mask'? It only allows what you want to see.

Also, don't forget in the array [] the last slot is for size. So char name[5][1] will get you name[0-4][0], so cin.get(dummy.name[i][0], 1); will do the trick.

u p d a t e d .. !!

#include <iostream>
#include <cstring>

using namespace std;


struct Student
{
    char name[5][2];
};

void in(Student &dummy)
{
    for(int i = 0; i < 5; ++i)
    {
       cin.get(dummy.name[i][1]);
    }
}

void out(Student &dummy)
{
    for(int j = 0; j < 5; ++j)
    {
        cout << dummy.name[j][1] << " || ";
    }
}

int main()
{
    Student nerd;
    in(nerd);
    cout << '\n';
    out(nerd);
    return 0;
}
</cstring></iostream>